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Dima020 [189]
2 years ago
14

Find the simplified product where sqrt 5x ( sqrt 8x^2 - 2 sqrt x)

Mathematics
2 answers:
Sliva [168]2 years ago
6 0

Answer:

D is your answer

Step-by-step explanation:

Just did it and it was right : )

Also for anyone else who needs the other answers they are as follows:

1. D. 6x^4  then  C. 3x^4

2. B. -30x^2 \sqrt{2x}  then  C. 4x^4^3 \sqrt{2x^2}

3. D. 2x\sqrt{10x} - 2x \sqrt{5}

4. B. 32x^2 \sqrt[3]{2x} -8x^3

5. A. -22  then  C. 4x^4 \sqrt{5} +2x^2 \sqrt{3x} + 4x^3 \sqrt{30}  +6x \sqrt{2x}

6. B. x^\frac{2}{12}* y^\frac{9}{12}  then  C. \sqrt[12]{x^2*y^9}

<h2><u><em>These answers are for!!!!</em></u></h2>

<em>NC Math 2 -22092x0</em>

<em>Multiplying Radicals</em>

Assignment

<em>Due March 11</em>

<em>Multiplying radicals with like indices.</em>

alukav5142 [94]2 years ago
3 0

Answer:

40x^3 -10x

Step-by-step explanation:

Used math-way to solve this! I'm sorry if wrong, x

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Answer:

x=0.5355 or x=-6.5355

First step is to: Isolate the constant term by adding 7 to both sides

Step-by-step explanation:

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