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agasfer [191]
3 years ago
10

The google android mobile operating system is a proprietary system, for use on only approved devices.​

Computers and Technology
1 answer:
balandron [24]3 years ago
7 0
I would choose b. False
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A ____ object is used to hold data that is retrieved from a database via the OleDbDataAdapter connection. a. DataRecord b. DataS
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Monster Collector
Lera25 [3.4K]

Answer:

In java:

import java.util.*;

public class Main{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 int monsternum, usernum;

 int count = 0;

 Random rand = new Random();

 String [] monsters = {"wild pikamoo","wild bulbaroar"};

 for(int i =0;i<2;i++){

     monsternum = rand.nextInt(5);  

     System.out.print("A "+monsters[i]+" appears! Guess a number between 1 and 5: ");

     usernum = input.nextInt();

     if(monsternum == usernum){      count++;      System.out.println("Congratulations, you caught a "+monsters[i]+"!");  }

 else{      System.out.println("You almost had it, but the monster escaped.");  }

 

 }

 System.out.println("There are no more monsters to encounter!");

 System.out.println("You caught "+count+" monsters of 2");

 if(count!=2){      System.out.print("Keep training to be the very best!");  }

 else{      System.out.print("You're the monster collector master!");  }

}

}

Explanation:

This declares monster and user number as integers

 int monsternum, usernum;

Initialize count to 0

 int count = 0;

Call the random object

 Random rand = new Random();

Create a string array to save the monster names

 String [] monsters = {"wild pikamoo","wild bulbaroar"};

Iterate for the 2 monsters

 for(int i =0;i<2;i++){

Generate a monster number

     monsternum = rand.nextInt(5);  

Prompt the user to take a guess

     System.out.print("A "+monsters[i]+" appears! Guess a number between 1 and 5: ");

Get user guess

     usernum = input.nextInt();

If monster number and user guess are equal, congratulate the user and increase count by 1

<em>      if(monsternum == usernum){      count++;      System.out.println("Congratulations, you caught a "+monsters[i]+"!");  } </em>

If otherwise, prompt the user to keep trying

<em>  else{      System.out.println("You almost had it, but the monster escaped.");  }  </em>

<em>  } </em>

Print no monsters again

 System.out.println("There are no more monsters to encounter!");

Print number of monsters caught

 System.out.println("You caught "+count+" monsters of 2");

Print user score

<em>  if(count!=2){      System.out.print("Keep training to be the very best!");  } </em>

<em>  else{      System.out.print("You're the monster collector master!");  } </em>

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An app builder wants to show groups as the last navigation menu item in the Salesforce1 mobile app. However, the app builder is
tatyana61 [14]

Answer:

Option B is the correct answer.

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Other option is not true because they are not according to the following statement.

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Zigmanuir [339]

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Use the function varimp() on the output of train() and save it to an object called imp object.

<h3>What is the classification that has More than Two Classes and the Caret Package</h3>

In the Classification that has More than Two Classes and the Caret Package section, one need to use the methods that can be able to adapt to higher  forms or dimensions and through a lot of different machine learning algorithms.

Note that varImp is seen as a generic method for calculating variable .

Hence, Use the function varimp() on the output of train() and save it to an object called imp object.

Learn more about Computer function from

brainly.com/question/17048576

#SPJ1

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