Answer:
The answer to this question can be described as follows:
a) True
b) False
c) False
d) False
e) False
f) True
Explanation:
In option a, PATA device is used to connect the hard drives into systems. Its title suggests, depends on parallel transmitting technology, contrasted to the compulsive-signaling tools.
In option b, SATA1 is a first-generation device, and SATA3 third generation, that's why it is wrong.
In option c and option d, both were wrong because RAID 0 and RAID 5 are Cloud computing software for storing data.
In option e, An internal SATA data cable with an eSATA port can not be used as an additional connection is provided by the eSATA port.
In option f, It is true because there are 7 pins in internal SATA.
So you are gonna read that whole paragraph and then answer the question or describe what you learned about
Answer:
Option B is the correct option.
Explanation:
<u>The following are three core principles of Google ads</u>.
1- Relevance: It lets you link with that of the relevant people, with that of the right information at the appropriate moment. In simple words, It establishes the link with a specific user, with that information which is useful for that person at the correct time.
2- Control: Google Ads provides the user with full control of your own overall budget. In other words, it provides the user a good facility of posting their ads online in that cost which satisfy the user.
3- Results: Pay for those results including visits to your site or requests for your service. Their testing devices make it even easier and seeing how your web, software, and advertisements do.
Explanation:
Step one
The maximum size of data field in each fragment = 480
(because there are 20 bytes IP header) Thus the number of required
fragments
thus the number of required fragment is 4
Step two
Each fragment will have identification number 291. each fragment except the last one will be of size 500 bytes (including IP header). the offset of the fragments will be 0, 60, 120, 180. each of the first 3 fragments will have
flag = 1; the last fragment will have flag =0