Question

A tank of water holding 528 kL of water begins to empty at a rate of 10 kL/min. At the same time, another tank, which is empty, begins to fill at a rate of 14 kL/min. Let k represent the number of kiloliters of water and let t represent time in minutes. The system models this situation. How long will it take for the tanks to hold equal amounts of water, and how much water will that be? k = 528 – 10t. . k = 14t.
It will take minutes__ for both tanks to hold equal amounts of water. They will each hold__ kiloliters.

Answer 1

We just need to solve the system.
k = 528 – 10t
k = 14t

14t=528-10t
24t=528
t=22 minutes

k=14*22=308 kl

Final answer: It will take 22 minutes  for both tanks to hold equal amounts of water. They will each hold 308 kiloliters.