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3 years ago

A company prices its tornado insurance using the following assumptions:

Mathematics

1 answer:

ziro4ka [17]3 years ago

8 0

Answer:

.441320612

44.132%

Step-by-step explanation:

This is binomial

fewer than 3 is equal to p(0)+p(1)+p(2)

$p(0)={19\choose0}*.15^0*(1-.15)^{19}=.045599448\\p(1)={19\choose1}*.15^1*(1-.15)^{18}=.152892268\\p(2)={19\choose2}*.15^2*(1-.15)^{17}=.242828896\\p(0)+p(1)+p(2)=.441320612$

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In a trivia competition, Shannon's score was up to 900 points. Then she scored -400 points in

AnnyKZ [126]

Answer:

Step-by-step explanation:

Her score after the two competitions was 500

hope this answer helps you

5 0

3 years ago

Read 2 more answers

1/17b = 90????<br> Please start it as multiplying both sides with the denominator

Ilya [14]

Answer:

b = 1530

Step-by-step explanation:

1/17 b = 90

(17)1/17b = 90 × 17

b = 1530

3 0

3 years ago

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The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago

5. A flock of geese flies 50 miles per hour. Write a linear

MrMuchimi

Answer:

y=50x+0

Step-by-step explanation:

y=mx+b is y-intercept form

I will make x= hours and y= distance (miles)

every 1 you add to x has to represent 50 miles

for the y intercept, it was unspecified so I assumed 0

Hope this helps :)

7 0

3 years ago

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A fountain is made up of two semicircles and a quarter circle. Find the perimeter of the fountain. Round to the nearest hundredt

Masja [62]

Answer:

75.40 feet

Step-by-step explanation:

For the two small semicircles, the circumference is $\frac{1}{2} 2\pi r$ , or just $\pi r$ . Since the radius is 1/2(16), or 8, the combined circumference of the two semicircles is 16 $\pi$ . Now, for the area of the quarter circle in the middle, we see that its radius is 16, and so its circumference is $\frac{1}{4} 2\pi r$ , or $\frac{1}{2} \pi 16$ = 8 $\pi$ . So, the perimeter of the fountain is 16 $\pi$ + 8 $\pi$ = 24 $\pi$ , or about 75.40 feet.

Hope this helped! :)

4 0

3 years ago