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2 years ago

I need help plz help me

Mathematics

1 answer:

grandymaker [24]2 years ago

6 0

U have to show me the table so i can answer you problem

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a rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1

AleksandrR [38]

Graph images undergo transformations, one of the types of transformations are rotations.
rotation is done when each point of the image rotates 90° around a point in the counterclockwise manner.
when rotation is done, (x,y) -> (-y,x)
therefore when taking points from image to original then the reverse is done ;
(-y,x) --> (x,y)
the coordinates of image point q' is (-3,4)
before rotation then the coordinates are (4,3)
answer is (4,3)

4 0

3 years ago

Read 2 more answers

Make g the subject of the formula in w = 7 - sqrt g

sukhopar [10]

Answer: g = w² - 14w + 49

$w=7-\sqrt{g}\\\\=> \sqrt{g} =7-w \\\\g=(7-w)^{2}=49-14w+w^{2}$

Step-by-step explanation:

3 0

2 years ago

Which answer describes the transformation of f(x)=log2(x−5)−2 from the parent function g(x)=log2x ? A) It is the graph of g(x) s

damaskus [11]

Answer:

It is the graph of g(x) shifted 5 units right and 2 units down.

Step-by-step explanation:

Given : f(x)=log_2(x−5)−2

the parent function g(x)=log_2(x)

To get f(x) , 5 is subtracted from x

If we add any number with x then we shift left

If we subtract any number from x then we shift right

Here 5 is subtracted from x , so we shift 5 units right

Also -2 at the end

If we add any number at the end , then we shift up

if we subtract any number at the end , then we shift down

Here 2 is subtracted at the end , so we shift 2 units down

It is the graph of g(x) shifted 5 units right and 2 units down.

4 0

2 years ago

A meter stick casts a shadow 2.4 m long at the same time a flagpole casts a shadow 9.7 m long. How tall is the flagpole

Luda [366]

The first thing we are going to do is draw a diagram of the situation to help us to solve the situation.
We an draw tow similar triangle between the length of the shadows and the height of the stick and the pole.
Since <span>meter stick has a length of 1 meter, the height of our smaller triangle is 1 meter. Let </span> $h$ be height of of the pole. Since both triangles are similiar we can establish a proportion between their corresponding sides and solve for $h$ :
$\frac{h}{1} = \frac{9.7}{2.4}$
$h=\frac{9.7}{2.4}$
$h=4.04$

We can conclude that the pole is 4.04 meters tall.

8 0

3 years ago

Consider two unique parallel lines. What aspects of these two lines are the same? What aspects of these two lines would have to

nalin [4]

Their slopes would be the same but their positions or points ( if the lines were on a graph) would be different.

5 0

3 years ago