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3 years ago

Can You Please Help Me

Mathematics

2 answers:

Illusion [34]3 years ago

8 0

Answer:

A: YES

B: NO

C: YES

Step-by-step explanation:

uhm, if you really need an explanation, here it goes

the opposite of an integer is its opposite value or if its a postitve integer the oposite woud be the negative integer, and thats all i got, hope this helps.

Sergeeva-Olga [200]3 years ago

4 0

A.) Yes

B.) No

C.) Yes

Hope this helps.

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Rewrite the expression as an equivalent power with a negative exponent. a. 1/49 b. 27/125

Hunter-Best [27]

$\dfrac{1}{49}=\left(\dfrac{1}{7}\right)^2=7^{-2}\\
\dfrac{27}{125}=\left(\dfrac{3}{5}\right)^3=\left(\dfrac{5}{3}\right)^{-3}$

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3 years ago

Find the missing terms of the aritmetic sequence 5,a2,a3,a4,-11

Allushta [10]

A2= 1
a3=-3
a4=-7
the common difference is -4

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2 years ago

Factor the expression completely. 625x4 - 256y4

scoundrel [369]

Answer:

(625 • (x4)) - 28y4

54x4 - 28y4 3.1 Factoring: 625x4-256y4

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 625 is the square of 25

Check : 256 is the square of 16

Check : x4 is the square of x2

Check : y4 is the square of y2

Factorization is : (25x2 + 16y2) • (25x2 - 16y2) 3.2 Factoring: 25x2 - 16y2

Check : 25 is the square of 5

Check : 16 is the square of 4

Check : x2 is the square of x1

Check : y2 is the square of y1

Factorization is : (5x + 4y) • (5x - 4y)this is the answer: (25x2 + 16y2) •(5x + 4y) • (5x - 4y)

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3 years ago

2132 plus what equals 2650

Studentka2010 [4]

518 is the answer. **

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3 years ago

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The ordered pair (a, b) gives the location of point P on the coordinate plane. The value of b is negative. The value of a is not

sergejj [24]

Answer:

Quadrant III ( C )

Quadrant IV ( D )

Step-by-step explanation:

Ordered pair ( a, b )

gives a point P on the coordinate plane

( a, b ) = ( x, y )

given : b = negative ( y-axis )

a ≠ 0 ( i.e. a = negative or positive ) ( x -axis )

Therefore point P is located in the : Third and fourth quadrants

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2 years ago

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Can You Please Help Me ​

Can You Please Help Me