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masha68 [24]
4 years ago
9

in a fireplace, about 3/4 of an 18-inch log will burn in 1/3 of an hour. How many hours will it take to burn 2 1/2 logs?

Mathematics
1 answer:
olga_2 [115]4 years ago
3 0
3/4 =1/3 hour
how long to burn 2 and 1/2

3/4=1/3hour
1/4=1/9 hour
4/4=1=4/9hour
1/2=2/4
1/2=2/9hour
 
2 and 1/2=1+1+1/2=4/9+4/9+2/9=10/9=9/9+1/9=1+1/9=1 and 1/9



answer is C. 1 and 1/9 hour
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7 7/8= 63/8

3 1/4= 13/4

63/8 -13/4  we bring to the same denominator

(63-26)/8=  37/8
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Problem PageQuestion Flying against the jetstream, a jet travels 3050 miles in 5 hours. Flying with the jetstream, the same jet
goblinko [34]

Answer: the rate of the jet in still air is 685 mph and the rate of the jetstream is 75 mph

Step-by-step explanation:

Let x represent the rate of the jet in still air.

Let y represent the rate of the jet jetstream.

Distance = speed × time

Flying against the jetstream, a jet travels 3050 miles in 5 hours. This means that the total speed of the jet would be (x - y) mph. Therefore,

3050 = 5(x - y)

3050/5 = x - y

x - y = 610 - - - - - - - - - - - - - -1

Flying with the jetstream, the same jet travels 3800 miles in 4 hours. This means that the total speed of the jet would be (x + y) mph. Therefore,

3800 = 4(x + y)

3800/5 = x + y

x + y = 760 - - - - - - - - - - - - - -2

Adding equation 1 to equation 2, it becomes

2x = 1370

x = 1370/2 = 685mph

Substituting x = 685 into equation 1, it becomes

685 - y = 610

y = 685 - 610 = 75mph

3 0
3 years ago
Write an algebraic expression for the word phrase. five fewer than d days d – 5 5 + d 5 – d d + 5
Troyanec [42]

Answer:

(d-5)

Step-by-step explanation:

we know that

The phrase"five fewer than d days" is equal to subtract 5 from the number d

so

d minus 5-----> (d-5)

7 0
3 years ago
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if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?
Kay [80]

Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • There are 9 rolls, hence n = 9.
  • Of the six sides, 2 are 3 or 4, hence p = \frac{2}{6} = 0.3333

The desired probability is:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026

P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

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