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Sindrei [870]
3 years ago
13

In a long-distance relay contest, Team A completed the race in 5 2/3 hours, and Team B completed the race in 294 minutes. How mu

ch longer did it take Team A to complete the race than Team B? Answer the question in hours first, and then in minutes.
Mathematics
1 answer:
charle [14.2K]3 years ago
7 0

Answer:

46 minutes.

Step-by-step explanation:

2/3 of an hour = 40 minutes.

So....5 hours 40 minutes.

294 minutes is 6 minutes shy of 5 hours. (300 minutes)

40 + 6 = 46 minutes

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Suppose that a sample of size 100 is to be drawn from a population with standard deviation L0. a. What is the probability that t
NARA [144]

Answer:

The probability that the sample mean will lie within 2 values of μ is 0.9544.

Step-by-step explanation:

Here

  • the sample size is given as 100
  • the standard deviation is 10

The probability that the sample mean lies with 2 of the value of μ is given as

                                            P(| \bar{X}-\mu|

Here converting the values in z form gives

P(-2

Substituting values

P(-2

From z table

P(z\leq 2)=0.9772\\P(z\leq -2)=0.0228\\P(-2\leq z\leq 2)=P(z\leq 2)-P(z\leq -2)\\P(-2\leq z\leq 2)=0.9772-0.0228\\P(-2\leq z\leq 2)=0.9544\\

So the probability that the sample mean  will lie within 2 values of μ is 0.9544.

5 0
3 years ago
It takes 12 men 8 days to construct a wooden shed. How many days will 15 men take?
Fynjy0 [20]

Answer:

10 days.

Step-by-step explanation:

8÷12 (because you can not divide people.

.666

take that and multiply it by 15

you will get 10

6 0
3 years ago
The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that
salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

X \sim Binom(n=20, p=0.411)

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

P(X\geq 1 ) = 1-P(X

And we can find the individual probability:

P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253

And then:

P(X\geq 1 ) = 1-P(X

And since we want the probability in the 3 classes we can assume independence and we got:

P= 0.99997^3 = 0.9992

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

X \sim Binom(n=20, p=0.411)

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

P(X\geq 1 ) = 1-P(X

And we can find the individual probability:

P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253

And then:

P(X\geq 1 ) = 1-P(X

And since we want the probability in the 3 classes we can assume independence and we got:

P= 0.99997^3 = 0.9992

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0
3 years ago
Unit rate feet per second 180 miles over 2 hours
Tatiana [17]
So that is equal to 180 miles per 2 hours which is 90 miles per hour if each hour has the same m/hr rate.
You can set up a proportion:
let x = number of miles per hour
\frac{x}{180} = \frac{1}{2}
cross multiply and you get
2x=180
divide both sides by 2 and you get
x=90
so you get the same answer both ways,
90 miles per hour
5 0
3 years ago
Find the slope of the graph
olga55 [171]
3/2 since you move 3 spaces horizontally (x) and 2 spaces up (y)
3 0
2 years ago
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