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3 years ago

How to write 24/39 in simplest form

Mathematics

2 answers:

Georgia [21]3 years ago

6 0

Answer:

8/13

Step-by-step explanation:

uysha [10]3 years ago

3 0

Answer:

8/13

Step-by-step explanation:

Note that both 24 and 39 are evenly divisible by 3.

Thus, 24/39 can be reduced to 8/13, which is the third answer choice.

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Find the fifth term in the sequence<br>that is defined as follows:<br>an = 2n

Rainbow [258]

Answer:

$a_{5}=10$

Step-by-step explanation:

If you want to find the 5th term of a sequence or any term you have to substitute n for the desired term in your case the result is the following

$a_{n}=2n\\a_{5}=2(5)\\a_{5}=10$

7 0

3 years ago

The volume of a square pyramid is 72 inches square if the dimensions of the square are 6in by 6in what is the height of the pyra

Pani-rosa [81]

Answers is 2in

Step-by-step explanation: 6in•6in=36in•2in=72in

3 0

3 years ago

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Find the counterclockwise circulation and outward flux of the field Fequals7 xy Bold i plus 2 y squared Bold j around and over t

77julia77 [94]

Answer:

The counterclockwise circulation is $\frac{7}{12}$ and the outward flux is $\frac{11}{15}$

Step-by-step explanation:

We are given the field $F(x,y) = (7xy,2y^2)$ . A picture of the region and the path we are considering is attached. Recalll the following theorems.

Given a field of the form F(x,y)=(f(x,y),g(x,y) with f,g having continous partial derivates, C is a closed path counterclockwise oriented, R is the region enclosed by C and n is the normal vector pointing outwards of the path C. Then

$\oint_C F\cdot dr =\iint_R \frac{\partial f}{dy}- \frac{\partial g}{dx} dA$ (this one calculates the counterclockwise circulation)

$\oint_C F\cdot n ds =\iint_R (\frac{\partial f}{dx}+ \frac{\partial g}{dy} dA$ (This one calculates the outward flux)

Then, recall that in our case f(x,y) = 7xy, g(x,y)=2y^2[/tex]. Then

$\frac{\partial f}{dx} = 7y,\frac{\partial f}{dy} = 7x$

$\frac{\partial g}{dx}=0, \frac{\partial g}{dy} = 4y$ .

Note that we just need to describe our region R. The region R lies between the parabola y=x^2 and the line y=x. Thus, one way to describe the region is as follows $0\leq x \leq 1, x^2\leq y \leq x$ . Then, using the previous results, we get that

$\oint_C F\cdot dr =\int_{0}^{1}\int_{x^2}^{x}7x-0dydx = 7\int_{0}^1x(x-x^2)dx = 7 \left.(\frac{x^3}{3}-\frac{x^4}{4})\right|_{0}^1 = 7(\frac{1}{3}-\frac{1}{4}) = \frac{7}{12}$ (circulation)

$\oint_C F\cdot n ds=\int_{0}^{1}\int_{x^2}^{x}7y+4ydydx = \frac{11}{2}\int_{0}^1\left.y^2\right_{x^2}^{x}dx = \frac{11}{2}\int_{0}^{1}x^2-x^4 dx = \frac{11}{2}\left(\frac{x^3}{3}-\frac{x^5}{5})\right|_{0}^{1}=\frac{11}{2}(\frac{1}{3}-\frac{1}{5})=\frac{11}{15}$ (flux)

5 0

3 years ago

Which is the area of a circle with circumference of 15.7 units?( Use 3.14 for )

damaskus [11]

A = π(r²) --- r is radius

C = πd --- d is diameter

First, the circumference must be found. If the circumference is 15.7, plug it in.

15.7 = πd

We know what pi is.

15.7 = 3.14 (d)

Now, simply divide 3.14 by 15.7 to find the diameter (d). You get 5. Since the radius is half of the diameter, the radius is 2.5. Plug this into the area formula, and plug pi in, too.

A = 3.14(2.5²)

2.5 to the second power is 6.25.

A = 3.14(6.25)

Tada! Multiply, and you're left with 19.625!
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4 0

3 years ago

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Find equation of linear function represented by the table below in slope intercept form

icang [17]

Answer:

y=4x+3

Step-by-step explanation:

The slope of the line is (13-7)/(2-1)=4. The line equation is hence y=4x+3

7 0

3 years ago