Ask question

Ask question

All categories

3 years ago

8

If f(x) = (3/94), what is f(3)?

1 answer:

deff fn [24]3 years ago

5 0

Answer:

3/94

Step-by-step explanation:

You might be interested in

What is 1 plus 894? I need help please

labwork [276]

It's is 895 because u add 4 with 1 so yeah it's 895

3 0

2 years ago

Read 2 more answers

A dinner platter is in the shape of a regular decagon the platter has an area of 161 in.² and a side length of 4.6 inches what's

cupoosta [38]

Number of sides= 10
Side length= 4.6 ( or in this case base)

161 sq inches / 10 = 16.1 area of triangle.

Area of triangle =(b<span>ase * </span>height)/2

16.1=(4.6*h)/2
multiply 16.1 by 2 (cancels the dividing the 2)

32.2=4.6*h
divid 32.2 by 4.6

<span>7 is the height of the triangle</span>

5 0

3 years ago

Country A has a growth rate of 4.9% per year. The population is currently 4 comma 151,000, and the land area of Country A is 1

kvv77 [185]

Answer:

There will be one person on 1 square yard of land after 1,892,147.588 years.

Step-by-step explanation:

Continuous exponential growth formula:

$P(t)=Pe^{rt}$

P(t)= Population after t years.

P= Initial population

r=rate of growth.

t= time in year

Given that,

Growth rate of country A (r)= 4.9% per year=0.049 per year.

Initial population (P)= 151,000.

Land area of country area= 14,000,000,000 square yards.

There will be one person on one square yard of land.

So, there will be 14,000,000,000 person for 14,000,000,000 square yard of land in country A.

P(t)=14,000,000,000 person

$\therefore 14,000,000,000= 151,000 e^{0.049t}$

$\Rightarrow e^{0.049t}=\frac{ 14,000,000,000}{ 151,000}$

Taking ln both sides

$\Rightarrow ln|e^{0.049t}|=ln|\frac{ 14,000,000,000}{ 151,000}|$

$\Rightarrow {0.049t}=ln|\frac{ 14,000,000,000}{ 151,000}|$

$\Rightarrow t}=\frac{ln|\frac{ 14,000,000,000}{ 151,000}|}{0.049}$

$\Rightarrow t}=1,892,147.588$ years

There will be one person for every square yard of land after 1,892,147.588 years.

7 0

3 years ago

PLEASE HELP WILL GIVE BRAINLIEST

vekshin1

Answer:

Step-by-step explanation:

Tod did not want the answer?

3 0

2 years ago

An article claims that 12% of trees are infested by a bark beetle. A random sample of 1,000 trees were tested for traces of the

inna [77]

Answer: 0.6812

Step-by-step explanation:

Let p be the population proportion of trees are infested by a bark beetle.

As per given: p= 12%= 0.12

Sample size : n= 1000

Number of trees affected in sample = 1000

Sample proportion of trees are infested by a bark beetle. = $\hat{p}=\dfrac{127}{1000}=0.127$

Now, the z-test statistic : $z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

So, $z=\dfrac{0.127-0.12}{\sqrt{\dfrac{0.12\times 0.88}{1000}}}$

$z=\dfrac{0.007}{\sqrt{\dfrac{0.1056}{1000}}}\\\\\\=\dfrac{0.007}{\sqrt{0.0001056}}\\\\\\=\dfrac{0.007}{0.010276}\approx0.6812$

Hence, the value of the z-test statistic = 0.6812 .

7 0

3 years ago