Answer:
2, less than the change in momentum
Explanation:
hope this helps!! :)
Answer:
<em>The thermal energy dissipated in A would be twice that in B</em>
Explanation:
Resistor B (RB)= R
Resistor A (RA)= 2 R
When they are connected in series the equivalent Resistance in the circuit would be;
Equivalent resistance = RA +RB = R + 2 R = 3 R;
From ohms law I = V/R
I = V/3 R
Now the thermal energy is the power dissipated by the circuit and can be obtained thus;
P =
Then,

Therefore Pa : Pb = 2: 1, this means that the thermal energy dissipated in A would be twice that in B
<h3><u>Answer;</u></h3>
The period of the wave is <u><em>4 seconds</em></u>
<h3>
<em><u>Explanation;</u></em></h3>
- <em><u>The period of a wave or periodic time is the time taken for one complete oscillation to occur.</u></em> In this case, one complete oscillation occurs when the wave moves from one crest to the next or a trough to the next. <em><u>This takes 4 seconds. Therefore the period is 4 seconds.</u></em>
- <em><u>Frequency on the other hand is the number of oscillations by a wave in one second. Thus, f = 1/T, that is frequency is the reciprocal of periodic time.</u></em>
Object B has a greater inertia i think, it has a greater momentum anyway
Answer:
Explanation:
When two coherent light beams travel different paths and arrive at a point , there will be difference in the length of path travelled by them . If this difference is zero then both will reinforce each other and their brightness will add up . Hence there will be constructive interference .
If their path difference is not zero but it is equal to odd multiple of their half wavelength like λ / 2 , 3 λ / 2 , 5 λ /2 , 7 λ /2 etc , then instead of reinforcing each other , they will destroy each other . This is called destructive interference . As a result of it , darkness will prevail at the point where they meet or interfere.