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kirza4 [7]
4 years ago
6

Why does mass not affect the period of a pendulum?

Physics
2 answers:
OverLord2011 [107]4 years ago
7 0
Time period can be written as 2π √L/g .....so it doesn't depend on mass !
PilotLPTM [1.2K]4 years ago
6 0
As the mass increases so will the force on the pendulum.

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Two points A=(+16) and B=(-4) At electric potential respectively find:
Damm [24]

Answer:

a. Point A

b. 20 V

c. 100 J

Explanation:

a. Point A is at a higher potential because there is a positive sign in front of its magnitude. Since it is a positive integral value, and has a higher magnitude than point B which is at -4, point A is thus at a higher potential than point B.

b. The potential difference between the two points ΔV = A - B

= +16 V - (-4 V)

= +16 V + 4 V

= + 20 V

c. The work done, W in moving a charge Q across a potential difference ΔV is W = QΔV

So, since Q = 5 C and ΔV = + 20 V  

W = QΔV

= 5 C × (+ 20 V)

= 100 J

4 0
3 years ago
What two pieces of information are crucial to understanding newton's second law?
lisabon 2012 [21]
The second Newton's law of motion states that the rate of change in momentum of a moving body is proportional to the resultant force. 
Therefore, to understand this law one must understand the concept of momentum and that a body in motion experiences force.
As far as momentum is concerned it is important to note that as a body moves the momentum changes with change in time and also that a body at rest has 0 momentum because its speed/velocity is zero.
It is this change in momentum with time that is proportional to the resultant force experienced by the body.
5 0
3 years ago
A drum rotates around its central axis at an angular velocity of 19.8 rad/s. If the drum then slows at a constant rate of 3.02 r
Debora [2.8K]

a) Time taken =6.39 s

b) Angle of rotation while coming to rest = 188.17 rad

<u>Explanation:</u>

Initial angular velocity of the drum \omega_{0} = 19.8 rad/s^{2}

Angular acceleration of the drum \alpha = -3.02 rad/s^{2}

a.) We know that

\omega =\omega_{0} + \alpha  t

0 =  19.8 - 3.02 t

t = \frac{19.8}{3.02}

t = 6.39s

b.) we know that

\theta = \omega_{0} t + \frac{1}{2} \alpha   t^{2}

\theta = 19.8 \times 6.39 + \frac{1}{2} \times 3.02 \times 6.39^{2}

\theta =188.17 rad

3 0
4 years ago
while doing supw at school,you found a picture of Guru rinpoche in a waste pit.what would be your course of action?​
koban [17]
Dude you gotta rewrite that I have no idea what the question is
7 0
3 years ago
The student applies a net force of 4.5 N to the 1.5 kg textbook.
Kitty [74]

Answer:

3 m/s²

Explanation:

acceleration = Force / mass;  4.5/1.5 = 3

4 0
3 years ago
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