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4 years ago

Why does mass not affect the period of a pendulum?

Physics

2 answers:

OverLord2011 [107]4 years ago

7 0

Time period can be written as 2π √L/g .....so it doesn't depend on mass !

PilotLPTM [1.2K]4 years ago

6 0

As the mass increases so will the force on the pendulum.

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A long hollow cylindrical conductor (inner radius = 2.0 mm, outer radius = 4.0 mm) carries a current of 12 a distributed uniform

11Alexandr11 [23.1K]

Here we can use ampere'a law to find the magnetic field

$\int B.dl = \mu_o i_{en}$

$B*2 \pi r = \mu_o (i_1 + \frac{i_2*\pi(3^2 - 2^2)}{\pi(4^2 - 2^2}$

$B*2 \pi*0.003 = 4\pi * 10^{-7} (12 + 5)$

$B = 4\pi * 10^{-7} (12 + 5)$

$B = 1.13 * 10^{-3} T$

3 0

3 years ago

True or false: Increasing the Young’s modulus of a beam in bending will cause it to deflect less.

Alinara [238K]

Answer:

false?

Explanation:

The higher the modulus, the more stress is needed to create the same amount of strain; an idealized rigid body would have an infinite Young's modulus.

5 0

3 years ago

Read 2 more answers

A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.

kherson [118]

Answer:

<em>a. The rock takes 2.02 seconds to hit the ground</em>

<em>b. The rock lands at 20,2 m from the base of the cliff</em>

Explanation:

Horizontal motion occurs when an object is thrown horizontally with an initial speed v from a height h above the ground. When it happens, the object moves through a curved path determined by gravity until it hits the ground.

The time taken by the object to hit the ground is calculated by:

$\displaystyle t=\sqrt{\frac{2h}{g}}$

The range is defined as the maximum horizontal distance traveled by the object and it can be calculated as follows:

$\displaystyle d=v.t$

The man is standing on the edge of the h=20 m cliff and throws a rock with a horizontal speed of v=10 m/s.

The time taken by the rock to reach the ground is:

$\displaystyle t=\sqrt{\frac{2*20}{9.8}}$

$\displaystyle t=\sqrt{4.0816}$

t = 2.02 s

The rock takes 2.02 seconds to hit the ground

The range is calculated now:

$\displaystyle d=10\cdot 2.02$

d = 20.2 m

The rock lands at 20,2 m from the base of the cliff

5 0

3 years ago

A car starts from rest at a stop light and reaches 20m/s in 3.5s. Determine the acceleration of the car

olga55 [171]

The car accelerated at around ~5.7 m/s

8 0

3 years ago

An automobile has a mass of 1200 kg. what is its kinetic energy, in kj, relative to the road when traveling at a velocity of 50

snow_lady [41]

One thing you should notice. It is kind of weird. Ke has no direction so that fact that it has velocities associated with it does not matter. It becomes a scaler (something measured by amount alone).

General Formula
Ke = 1/2 m v^2
Formula for this problem
Ke = 1/2 m (v2)^2 - 1/2 m (v1)^2

Givens
m = 1200 kg
v2 = 100 km/hr = 100 km/h * [1 hour / 3600 sec] * [1000 m/ 1km] = 27.8 m/s
v1 = 50 km / hr = 13.9 m/s

Substitution and work.
================
delta Ke = 1/2 1200 (27.8)^2 - 1/2 1200 (13.9)^2
delta Ke = 463704 - 115926
delta Ke = 34778 Joules
delta Ke = 34.8 kJ

The change is 34.8 kJ which means that the vehicle gains 34.8 kJ

5 0

3 years ago