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Eddi Din [679]
3 years ago
14

What is the kinetic energy of a 150gram object moving at a velocity of 100m/s?

Physics
1 answer:
allochka39001 [22]3 years ago
8 0

Answer:

kinetic energy = 1 ÷ 2 × mass ×velocity ^2

kinetic energy = 1 ÷ 2 × 0.15 × 100^2

Kinetic energy = 750 Joules

Explanation:

NOTE ; S.I unit of mass is kilograms

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ribosomes

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3 years ago
Read 2 more answers
Si la aceleración de gravedad en la superficie del planeta Mercurio es de 3,7 m/s2, entonces ¿cuál sería el peso de una persona
erica [24]

Answer:

W = 222 N.

Explanation:

The qiestion says" If the acceleration of gravity on the surface of the planet Mercury is 3.7 m / s2, then what would be the weight of a person with mass 60 kg on its surface? "

Mass of the person, m = 60 kg

The acceleration due to gravity on the surface of gravity is 3.7 m/s²

We need to find the weight of a person on the surface of Mercury.

Weight of an object is given by :

W = mg

So,

W = 60 kg × 3.7 m/s²

W = 222 N

Hence, the person will weigh 2222 N on the surface of Moon.

4 0
3 years ago
Brainliest if right.
jeka57 [31]

Answer:

the third law (for every action there is an equal and opposite reaction).

Explanation:

The skateboarder pushes backwards on the road (that is he applies a force on the road in a direction opposite the direction of intended motion). By Newton's third law, this action of the skateboarder causes an equal reaction of the road on the skateboarder in the opposite direction. Newton's third law states that action and reaction are equal but opposite in direction. So, the road in response to this backward force pushes the skateboarder in the forward direction causing the skateboarder and the skateboard to move in the forward direction.

5 0
2 years ago
What row of the periodic table does this element belong?
sladkih [1.3K]

Answer:

Group 18

Explanation:

This element has a full octet, therefore it is a noble gas, being in period 18. (I think its Argon if you need that too)

Hope that helps

3 0
3 years ago
1. Consider the point exactly halfway between the two wires. Can you adjust the current so that, with current passing through ea
chubhunter [2.5K]

Answer:

hello your question is incomplete attached below is missing part of the question

answer:

1 )  Magnetic field due to long current carrying wire : B = \frac{U_{0} I}{2\pi d}

Therefore the net magnetic field due the both wires ; B = B_{1} + B_{2} . when we adjust the current I_{1} = I_{2} then the Netfield (B ) = zero

2) The distance between the field lines are not equally spaced and this is because the separation between field lines increases with the increase in the distance between the wires

3) Increase in current through the wire will lead to increase in force and this can be explained via this equation

F = \frac{U_{0}I_{1}I_{2}   }{2\pi d }

Explanation:

1 )  Magnetic field due to long current carrying wire : B = \frac{U_{0} I}{2\pi d}

Therefore the net magnetic field due the both wires ; B = B_{1} + B_{2} . when we adjust the current I_{1} = I_{2} then the Netfield (B ) = zero

2) The distance between the field lines are not equally spaced and this is because the separation between field lines increases with the increase in the distance between the wires

3) Increase in current through the wire will lead to increase in force and this can be explained via this equation

F = \frac{U_{0}I_{1}I_{2}   }{2\pi d }

8 0
3 years ago
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