All categories

2 years ago

What is the kinetic energy of a 150gram object moving at a velocity of 100m/s?

Physics

1 answer:

allochka39001 [22]2 years ago

8 0

Answer:

kinetic energy = 1 ÷ 2 × mass ×velocity ^2

kinetic energy = 1 ÷ 2 × 0.15 × 100^2

Kinetic energy = 750 Joules

Explanation:

NOTE ; S.I unit of mass is kilograms

You might be interested in

A wire carries a current of 4.1 A. How many electrons per second are passing any cross sectional area of the wire? Enter your an

aivan3 [116]

To solve this problem it is necessary to apply the concepts related to Current and Load.

The current in terms of the charge of an electron can be expressed as

$i = \frac{q}{t}$

Where,

q = Charge

t = time

At the same time the Charge is the amount of electrons multiplied by the amount of these, that is

q = ne

Replacing in the first equation we have to

$i = \frac{q}{t}$

$i = \frac{ne}{t}$

Clearing n,

$n = \frac{it}{e}$

Here the time is one second then

$n = \frac{i}{e}$

$n = \frac{4.1}{1.6*10^{-9}}$

$n = 2.56*10^{19}electrons$

Therefore the number of electrons per second are passing any cross sectional area of the wire are $2.56*10^{19}electrons$

3 0

2 years ago

Resistance increases with the length of the wire

Marta_Voda [28]

If the length of the wire increases, then the amount of resistance will also increase.

1. Take a long piece of wire and cut it 10 pieces. Those pieces should all be different sizes, one should be 5___ (units in meter, cm, inches, etc.), and the next should be 5 ___ (units in meter, cm, inches, etc.) more than the one before.
2. Take one piece of wire and measure the resistance using ___ and record the results in the data table.
3. Repeat the previous step with all the pieces of wire.
4. Compare and contrast the results you have found.

I hope this helps a bit :)

4 0

2 years ago

You create a ramp using two text books and a 0.50m board. Using a timer you determine that a cart can roll down the ramp in 0.55

ahrayia [7]

Answer:

The velocity of the cart at the bottom of the ramp is 1.81m/s, and the acceleration would be 3.30m/s^2.

Explanation:

Assuming the initial velocity to be zero, we can obtain the velocity at the bottom of the ramp using the kinematics equations:

$v=v_0+at\\\\v^2=v_0^2+2ad$

Dividing the second equation by the first one, we obtain:

$v=\frac{v_0^2+2ad}{v_0+at}$

And, since $v_0=0$ , then:

$v=\frac{2ad}{at}\\\\v=\frac{2d}{t}\\\\v=\frac{2(0.50m)}{0.55s}\\\\v=1.81m/s$

It means that the velocity at the bottom of the ramp is 1.81m/s.

We could use this data, plus any of the two initial equations, to determine the acceleration:

$v=v_0+at\\\\\implies a=\frac{v}{t}\\\\a=\frac{1.81m/s}{0.55s}\\\\a=3.30m/s^2$

So the acceleration is 3.30m/s^2.

7 0

2 years ago

Which pair of elements has the most similar properties?

Vanyuwa [196]

The answer is B, because oxygen and sulfur are in the same group (group 6A)

7 0

2 years ago

Two identical light springs with spring constant k3 are now individually hung vertically from the ceiling and attached at each e

anyanavicka [17]

Answer:

Keq = 2k₃

Explanation:

We can solve this exercise using Newton's second one

F = m a

Where F is the eleatic force of the spring F = - k x

Since we have two springs, they are parallel or they are stretched the same distance by the object and the response force Fe is the same for the spring age due to having the same displacement

F + F = m a

k₃ x + k₃ x = m a

a = 2k₃ x / m

To find the effective force constant, suppose we change this spring to what creates the cuddly displacement

Keq = 2k₃

6 0

2 years ago