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4 years ago

Which ratio best defines theoretical probability?

Mathematics

2 answers:

zvonat [6]4 years ago

7 0

Theoretical probability is when all of the outcomes are equally likely.

The ratio that best represents this is

# of favorable outcomes : # of total outcomes.

ozzi4 years ago

5 0

Answer:

number of favorable outcome number of possible outcomes

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Lady bird [3.3K]

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3 years ago

prove that if f is integrable on [a,b] and c is an element of [a,b], then changing the value of f at c does not change the fact

Neko [114]

Answer with Step-by-step explanation:

We are given that if f is integrable on [a,b].

c is an element which lie in the interval [a,b]

We have to prove that when we change the value of f at c then the value of f does not change on interval [a,b].

We know that limit property of an integral

$\int_{a}^{b}f dt=\int_{a}^{c}fdt+\int_{c}^{b} fdt$

$\int_{a}^{b} fdt=f(b)-f(a)$ ....(Equation I)

Using above property of integral then we get

$\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b} fdt$ ......(Equation II)

Substitute equation I and equation II are equal

Then we get

$\int_{a}^{b}fdt= f(c)-f(a)+{f(b)-f(c)}$

$\int_{a}^{b}fdt=f(c)-f(a)+f(b)-f(c)=f(b)-f(a)$

$\int_{a}^{c}fdt+\int_{c}^{b}fdt=f(b)-f(a)$

Therefore, $\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b}fdt$ .

Hence, the value of function does not change after changing the value of function at c.

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3 years ago

Solve this equation graphically using table 5m-2n=4,m-4n=-1

DerKrebs [107]

Answer:

m = 1; n = 0.5

Step-by-step explanation:

5m - 2n = 4; m - 4n = - 1

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3 years ago

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Answer:

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Step-by-step explanation:

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no matter how you solve it, it will equal j = 1.

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3 years ago