3x-2y=6 thats The Problem I Need Help On

Mathematics

1 answer:

Roman55 [17]4 years ago

6 0

Solve for Y?

Subtract -3x.
Then didvidd by -2 to get Y by itself.

Y= 3/2y -3

X-Intercept: (2,0)
Y-Intercept: (0,-3)

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A box of cereal states that there are 81 calories in a 7-cup serving. What is the unit rate for calories

mr_godi [17]

Answer:

23.142857143 calories or 23 1/7 calories

The unit rate is calories per cup

Step-by-step explanation:

7- cup serving = 81 calories

2 cups = x calories

Cross Multiply

2 cups × 81 calories = 7 cups × x

x = 2 cups × 81 calories/7 cups

x = 23.142857143 calories or 23 1/7 calories

5 0

3 years ago

Suppose that you need to create a list of n values that have a specific known mean. Some of the n values can be freely selected.

Leno4ka [110]

As the problem indicates, degrees of freedom are the number of values that can be independently selected before it is necessary to choose specific values to arrive at the desired result.

The average, on the other hand, results from the sum of a list of values divided by the amount of values in the summed list.

Assume that the mean sought is $x$ and consider that the list is composed of a single element $a$ , in that case no random number can be selected, since the mean $x$ must correspond to that number.

If the list were composed of two elements $a$ and $b$ , one of the two values could be chosen randomly, and according to the chosen value the second should be the one whose sum with the previous one results in $2x$ , this given that the formula of the average $\sum\limits_{i=1}^n \frac{ x_{i}}{n}$ .

With three values $a$ , $b$ and $c$ , it is possible to select two freely, since the thirteen must be the one that balances the sum of $a+b$ , that is $(a + b) + c = 3x$ .

Thus, in general, with n values, it is possible to select $n-1$ values freely whose sum must be balanced by the last value so that the whole sum is $nx$ .