Answer for your question is on the picture below
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
Answer:
(x+3)⁴
Step-by-step explanation:
(1)x⁴
+
(4)x³.3
+
(6)x²3²
+
(4)x 3³
+
(1)3⁴
= x⁴+ 12x³+ 54x² + 108x + 81
Answer:
1.3(2)^t
Step-by-step explanation:
1.3(2)^t
You start with 1.3 because that is your inital amount, then you multiply by 2 because it doubles, and your exponent will be t (the number of weeks)
Answer:
(q,0)
Step-by-step explanation:
See the diagram given.
It is clear from the coordinates of the points given that point C (0,r) lies on the Y-axis and point E (-q,o) lies on the X-axis. Hence, point D must be on the X-axis.
ΔCDE being an isosceles triangle, the origin of the coordinate axes will be on the DE line and it will be at the midpoint of DE.
Therefore, ΔCDE will be symmetric with respect to the Y-axis and the coordinates of point D will be (q,0). (Answer)
