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vlada-n [284]
4 years ago
6

3x-2y=6 thats The Problem I Need Help On

Mathematics
1 answer:
Roman55 [17]4 years ago
6 0
Solve for Y?

Subtract -3x.
Then didvidd by -2 to get Y by itself.

Y= 3/2y -3

X-Intercept: (2,0)
Y-Intercept: (0,-3)

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Kevin wants to buy an area rug for his living room. He would like the area rug to be no smaller that 48 square feet and no bigge
mariarad [96]

Answer:

8-10 feet

Step-by-step explanation:

If the length of the carpet is two more than the width, the width can be expressed as x and the length can be expressed as x+2. This means that the area(x^2+2x) must be greater than 48 but no less than 80.

Now we can solve for both the maximum and minimum cases:

x^2+2x=48, x^2+2x-48=0, now we can factor, (x+8)(x-6)=0, and now we can use the Zero Product Property to find x=-8;x=6. Since we cant have negative width, x at least has to be equal to 6.

x^2+2x=80,x^2+2x-80=0, now we can factor, (x+10)(x-8), and now using the Zero Product Property to find x=-10;x=8, and since it must be positive, at most x can equal 8.

Now since the length is two more than the width, x, you add two to both of these values and get a range of 8-10 feet.

3 0
4 years ago
If f(x) = 2x – 3 and g(x) = 4x + 5, what is (f • g)(x)?
lorasvet [3.4K]

Answer:

Place the f(x) expression 2x-3 into the x in the g(x) expression 4x+5, so it will be 4(2x-3)+5; you can expand it out if you want

6 0
3 years ago
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Find the mean absolute deviation for the set {-32, 9, 11, 12}
Zolol [24]
<h3>Answer:</h3>

A

Step-by-step explanation:

{-32, 9, 11, 12}

first, find the mean (Find the sum of the data values, and divide the sum by the number of data values )

(-32) + 9 + 11 + 12 = 0

0/0 = 0

then, find the absolute value of the difference between each data value and the mean: |data value – mean|.

-32 - 0= -32

9 -0 = 9

11 -0 = 11

12 -0 = 0

finally, find the sum of the absolute values of the differences. Divide the sum of the absolute values of the differences by the number of data values.

0 - 0 / 4 = 0

answer is 0 (A)

7 0
4 years ago
Please help me with precalculus??<br>linear and angular speed
Anit [1.1K]
13)

there are 2π radians in 1 revolution, and there are 60 seconds in 1 minute, so keeping that in mind, then,

\bf \cfrac{4\underline{\pi} }{5~\underline{s}}\cdot \cfrac{rev}{2\underline{\pi} }\cdot \cfrac{60~\underline{s}}{min}\implies \cfrac{4\cdot 60~rev}{5\cdot 2~min}\implies \cfrac{240~rev}{10~min}\implies 24\frac{rev}{min}

14)

 \bf \textit{linear velocity}\\\\&#10;v=rw\quad &#10;\begin{cases}&#10;r=radius\\&#10;w=angular~speed\\&#10;----------\\&#10;v=32\frac{m}{sec}\\&#10;w=100\frac{rev}{min}&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\textit{let's convert \underline{w} to }\frac{radians}{sec}

\bf \cfrac{100~\underline{rev}}{\underline{min}}\cdot \cfrac{2\pi }{\underline{rev}}\cdot \cfrac{\underline{min}}{60~sec}\implies \cfrac{100\cdot 2\pi }{60~sec}\implies \cfrac{10\pi }{3~sec}\implies \cfrac{10\pi }{3}\frac{radians}{sec}\\\\&#10;-------------------------------\\\\&#10;v=rw\implies \cfrac{v}{w}=r\implies \cfrac{\frac{30~m}{sec}}{\frac{10\pi }{3~sec}}\implies r=\cfrac{30~m}{\underline{sec}}\cdot \cfrac{3~\underline{sec}}{10\pi }&#10;\\\\\\&#10;r=\cfrac{90}{10\pi }m

15)

what is the radians per seconds "w" in revolutions per minute?  just another conversion like in 13)

\bf \cfrac{\underline{\pi} }{3~\underline{sec}}\cdot \cfrac{rev}{2\underline{\pi }}\cdot \cfrac{60~\underline{sec}}{min}\implies \cfrac{60 ~rev}{3\cdot 2 ~min}\implies \cfrac{60 ~rev}{6 ~min}\implies 10\frac{rev}{min}
4 0
4 years ago
bill took a nap for 1 1/4 hour on friday and then took a nap for 3/4 hour on tuesday. how much longer was Bill's nap on friday?
sertanlavr [38]
1/2 (2/4) of an hour longer. If you take 1 1/4 and subtract 3/4 you get 2/4=1/2
4 0
3 years ago
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