3 years ago

Simplify the expression where possible(X^ 4 y^2)^3

Mathematics

1 answer:

Pani-rosa [81]3 years ago

6 0

<span>(X^ 4 y^2)^3
= x^12 y^6

hope it helps</span>

You might be interested in

15 pts!

shusha [124]

Answer:

They will have 53 CDs when they have the same amount. You have to add the amounts 5 times

Step-by-step explanation:

8+9=17+9=26+9=35+9=44+9=53

18+7=25+7=32+7=39+7=46+7=53

Hope this helps

Please mark me as brainliest

3 0

3 years ago

What is add 2x-1 to 5x+ 4? Thanks

Maksim231197 [3]

for this problem the answer is 9x-3

7 0

2 years ago

Read 2 more answers

What is 10 2/5 times 15 5/6!<br><br> Thanks

svet-max [94.6K]

10 2/5 times 15 5/7 is 5,720/35 which is 163 15/32 in mixed number

3 0

3 years ago

Original price of television is $729 , 18%of the original price , 6% tax applied after discount

Margaret [11]

It’s $1,903 Bc i just did that question

8 0

2 years ago

Read 2 more answers

Complete the following exercises by applying polynomial identities to complex numbers. Factor x2 + 64. Check your work. Factor 1

Mumz [18]

$x^2+64=x^2-(8i)^2=(x-8i)(x+8i)$

$16x^2+49=(4x)^2-(7i)^2=(4x-7i)(4x+7i)$

$(x+9i)^2=x^2+2x\cdot9i+(9i)^2=x^2+18xi+81i^2=x^2+18xi-81=x^2-81+18xi$

$(x-2i)^2=x^2-2x\cdot2i+(2i)^2=x^2-4xi+4i^2=x^2-4xi-4=x^2-4-4xi$

$(x+(3+5i))^2=x^2+2x(3+5i)+(3+5i)^2\\\\=x^2+6x+10xi+3^2+2\cdot3\cdot5i+(5i)^2\\\\=x^2+6x+10xi+9+30i+25i^2=x^2+6x+10xi+9+30i-25\\\\=x^2+6x+10xi+30i-16=x^2+6x-16+(10x+30)i$

$Used:\\i^2=-1\\\\a^2-b^2=(a-b)(a+b)\\\\(a+b)^2=a^2+2ab+b^2$

4 0

3 years ago

Read 2 more answers