$4\sqrt{9}\\\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=4\sqrt{3^2}\\\\\mathrm{Apply\:radical\:rule}:\quad \sqrt{a^2}=a,\:\quad \:a\ge 0\\\sqrt{3^2}=3\\\\=4\times\:3\\\\=12$

5 0

3 years ago

the width of a rectangle is 2 units less than the length.The area of the rectangle is 63 units. What is the length, in units, of

Anton [14]

Answer:

Width = 7. Length = 9.

Step-by-step explanation:

To get the the size of the width, it says that L = (W + 2), so we put in W+2 as a substitute for L. Now we have the equation the area or 63 = W x (W+2). I'm not so great with these problems so I typically just plug in a number for W till I get the area, and put w into the L = W + 2 equation to get L.

5 0

4 years ago

Tommy is thinking of a number between 800 and 900 He divides it by 4 and there is a remainder of 1 He divides it by 5 and there

Finger [1]

Answer:

841

Step-by-step explanation:

If the number is divided by 4 and the remainder is 1, the last digit must be 1, 3, 5, 7 or 9.

If the number is divided by 5 and the remainder is 1, the last digit must be 6 or 1.

So we already know the last digit must be 1.

The numbers between 800 and 900, with last digit 1, that divided by 6 have a remainder of 1 are:

811, 841, 871

The numbers between 800 and 900, with last digit 1, that divided by 7 have a remainder of 1 is just 841

So Tommy's number is 841.

5 0

3 years ago