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Lelechka [254]
3 years ago
15

Find the indicated limit. ModifyingBelow lim With x right arrow 8 StartRoot 7 x minus 2 EndRoot Select the correct choice below

and fill in the answer box within your choice. A. ModifyingBelow lim With x right arrow 8 StartRoot 7 x minus 2 EndRoot ​= nothing ​(Type an exact​ answer, using radicals as​ needed.) B. The limit does not exist.
Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0

Answer:

3\sqrt{6}

Step-by-step explanation:

We are to determine the limit below.

\lim _{x \rightarrow8}\sqrt{7x-2}

Plug in 8 into the function.

\lim _{x \rightarrow8}\sqrt{7x-2}=\sqrt{7(8)-2}\\=\sqrt{56-2}\\ =\sqrt{54}\\ =3\sqrt{6} \\\lim _{x \rightarrow8}\sqrt{7x-2}=3\sqrt{6}

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6)
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4 0
4 years ago
Can someone please help me out here?
fenix001 [56]
1. D
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3 years ago
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Triangle J K L is shown. Angle J L K is 105 degrees. The length of J K is 4.7 and the length of J L is 2.7.
cluponka [151]

Answer:

The approximate measure of angle K is 34°

Step-by-step explanation:

In ΔJKL

∠L = 105°

JK = 4.7

JL = 2.7

Sine Rule:

\frac{SinA}{a} = \frac{SinB}{b}= \frac{SinC}{c}

So,\frac{SinL}{JK} = \frac{SinK}{JL}\\\frac{SinL}{4.7} = \frac{SinK}{2.7}\\\frac{Sin 105}{4.7} = \frac{SinK}{2.7}\\\frac{Sin 105 \times 2.7}{4.7} = SinK\\\frac{(0.9659 \times 2.7)}{4.7} = Sin K\\\frac{2.60793}{4.7} = Sin K\\0.5549 = Sin K\\Sin^{-1}(0.5549)= K\\K = 33.70

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So, Option B is true

Hence The approximate measure of angle K is 34°

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