All categories

4 years ago

Find all the real square roots of -9/16

Mathematics

1 answer:

lakkis [162]4 years ago

4 0

Answer:

a. no real root

Step-by-step explanation:

sqrt(-9/16) has no real roots because negative numbers do not have two real numbers that are the same that multiply together to give a negative

-a * -a = a^2

a*a = a^2

There is no real number that gives -a^2

You might be interested in

9(x) = 2x-1 r(x) = -2x 2 2 Find the value of r(q (2)).

BabaBlast [244]

Answer:

Answer is -6

Step-by-step explanation:

$given \: q(x) = 2x - 1 \\ and \: r(x) = - 2x \\ r(q(2)) = r(2(2) - 1) \\ \: \: = r(4 - 1) \\ = r(3) \\ = - 2(3) \\ = - 6 \\ therefore \: r(q(2)) = - 6$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

6 0

3 years ago

PLEASE HELP!!!!!

Ad libitum [116K]

X+5=3 is the answer.

8 0

3 years ago

Does -2(z+3)-z=-z-4(z+2) have one,zero or infinite solutions

Andrew [12]

Hello from MrBillDoesMath!

Answer:

One solution (z = -1)

Discussion:

-2(z+3)-z=-z-4(z+2) =>

-2z -6 -z = -z -4z - 8 =>

-3z -6 = -5z -8 => add 6 to both sides

-2z = -5z -2 => add 5z to both sides

3z = -5z +5z -3 =>

3z = -3 =>

z = -1

Thank you,

MrB

6 0

4 years ago

When the fraction below is written as a decimal, how many digits are in the smallest

tiny-mole [99]

Answer: I THINK it's A

6 0

3 years ago

what is the length of the longest side of a triangle that has the vertices (2, 6), (-4, 6), and (-4, 4)? a. 2/10 units b. 40 uni

rewona [7]

Length (2, 6) to (-4, 6) is sqrt((x2 - x1))^2 + (y2 - y1)^2) = sqrt((-4 -2)^2 + (6 - 6)^2) = sqrt((-6)^2 + 0) = 6

Length (2, 6) to (-4, 4) is sqrt((-4 - 2)^2 + (4 - 6)^2) = sqrt((-6)^2 + (-2)^2) = sqrt(36 + 4) = sqrt(40) = 2sqrt(10) units

Length (-4, 6) to (-4, 4) is sqrt((-4 - (-4))^2 + (4 - 6)^2) = sqrt(0^2 + (-2)^2) = 2

Therefore, the length of the longest side is 2sqrt(10) units

4 0

3 years ago