Answer:
2.1
Step-by-step explanation:
This involves trigonometry. Since we need to find the value of a, we need to find a trig equation with a as the numerator. Luckily, we have one, tan. So, tan(20) is equal to a/6, right. So, using a calculator, tan(20) is approximately equal to 0.363. This times 6 should equal a. This is approximately around 2.1. Thus our answer is 2.1
Answer:
Step-by-step explanation:
Good question. It is important to know the answer.
The 9 means that there are a total of 20 objects. You want to select just 9 of them.
The situation is well described by C.
What are answer for can you put the answers please
Answer:
3x-8<23 and -4x+26>6
x<31/3 x<5
Step-by-step explanation:
3x-8<23
Add 8 to both sides
3x<31
Then divide 3 to both sides
x<31/3
and -4x+26>6
Minus 26 to both sides
-4x>-20
You divide -4 to both sides
Keep in mind that everytime you divide a negative the inequality will change so > will be <
x<5
Answer and step-by-step explanation:
The polar form of a complex number 
is the number 
where 
is called the modulus and 
is called the argument. You can switch back and forth between the two forms by either remembering the definitions or by graphing the number on Gauss plane. The advantage of using polar form is that when you multiply, divide or raise complex numbers in polar form you just multiply modules and add arguments.
(a) let's first calculate moduli and arguments
now we can write the two numbers as
(b) As noted above, the argument of the product is the sum of the arguments of the two numbers:
(c) Similarly, when raising a complex number to any power, you raise the modulus to that power, and then multiply the argument for that value.
![(z_1)^1^2=[4e^{-i\frac \pi6}]^1^2=4^1^2\cdot (e^{-i\frac \pi6})^1^2=2^2^4\cdot e^{-i(12)\frac\pi6}\\=2^2^4 e^{-i\cdot2\pi}=2^2^4](https://tex.z-dn.net/?f=%28z_1%29%5E1%5E2%3D%5B4e%5E%7B-i%5Cfrac%20%5Cpi6%7D%5D%5E1%5E2%3D4%5E1%5E2%5Ccdot%20%28e%5E%7B-i%5Cfrac%20%5Cpi6%7D%29%5E1%5E2%3D2%5E2%5E4%5Ccdot%20e%5E%7B-i%2812%29%5Cfrac%5Cpi6%7D%5C%5C%3D2%5E2%5E4%20e%5E%7B-i%5Ccdot2%5Cpi%7D%3D2%5E2%5E4)
Now, in the last step I've used the fact that 
, or in other words, the complex exponential is periodic with 
as a period, same as sine and cosine. You can further compute that power of two with the help of a calculator, it is around 16 million, or leave it as is.
