Find the slope of the line that passes through (1,3) and (-3,0)

A mini cooper is 120 inches long. A truck is 83% longer than the car. How long is the truck?

tamaranim1 [39]

Answer:A 16-ounce can of mixed nuts includes 6 ounces of cashews and 10 ounces of almonds. What is the ratio of almonds to mixed nuts in this can of nuts?

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Please Help due today

g100num [7]

Answer:

the awnser should be 4.47214 because it's the approximate value of 2√5

8 0

2 years ago

Joanne had $115 to spend at the mall. She spent 23% of that money on a shirt. How much did Joanne spend on the shirt?

-Dominant- [34]

The answer would be $26.45.
What you do is on a calculator: 115 x 23%
Hope this helps :)

3 0

3 years ago

Which statements are true? Select three options. ∠F corresponds to ∠F'. Segment EE' is parallel to segment FF'. The distance fro

Gwar [14]

Answer:

The correct options are (1), (3) and (5).

Step-by-step explanation:

The two triangles are shown below.

The measure of ∠F corresponds to ∠F'.

The distance between the points D and origin is of 9 units.

And the distance between the points D' and origin is 3 units.

Thus, the distance from point D' to the origin is One-third the distance of point D to the origin.

Check for similarity:

$\frac{D'F'}{DF}=\frac{D'E'}{DE}=\frac{F'E'}{FE}=\frac{1}{3}$

Thus, the △DEF is similar to △D'E'F'.

Thus, the correct options are (1), (3) and (5).

4 0

3 years ago

A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3>Solution:</h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

The area of rectangle is given as:

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

General form of quadratic equation is

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0

3 years ago