All categories

3 years ago

How many square feet of outdoor carpet will we need for this hole

Mathematics

1 answer:

Fed [463]3 years ago

4 0

Answer:

40 ft²

Step-by-step explanation:

The shape of the outdoor carpet can be decomposed into 2 triangles and 1 rectangle

✔️Area of triangle 1:

Area = ½*bh

b = 6 - 3 = 3 ft

h = 11 - 7 = 4 ft

Area of triangle 1 = ½*3*4 = 6 ft²

✔️Area of triangle 2:

Area = ½*by

b = 2 ft

h = 3 ft

Area of triangle 2 = ½*2*3 = 3 ft

✔️Area of rectangle = L × W

L = 11 ft

W = 3 ft

Area of rectangle = 11 × 3 = 33 ft

✅area of outdoor carpet = 4 + 3 + 33 = 40 ft²

You might be interested in

Find the volume of the cube

miskamm [114]

Answer:

The volume of cube is 125 cm³.

Step-by-step explanation:

Given that the formule of volume of cube is, V = length×width×height. Cube is a 3D form of square, so the sides of the cube are all the same. You have to substitute 5 into the formula,

Let length be 5 cm,

Let width be 5 cm,

Let height be 5 cm,

Volume = 5×5×5

= 125 cm³

7 0

3 years ago

Read 2 more answers

Small squares with sides 4 cm were cut from each of the corners of a square piece of cardboard. then it was folded into an open-

DENIUS [597]

Suppose the length of the card board was x cm by x cm
After squares of 4cm was cut from the corner, the dimension for the box will be:
length=(x-8) cm
width=(x-8) cm
height=4 cm
thus the volume will be:
V=length*width*height
V=4×(x-8)×(x-8)=144
x²-16x+64=36
this can be simplified to form a quadratic equation given by:
x²-16x+28=0
solving the quadratic equation we get:
x=2 or x=14
Thus we conclude that the original dimensions was:
length=14 cm ; width=14 cm

7 0

3 years ago

A rectangular Corn Hole area at the Recreation Center has a width of 5 feet and a length of 10 feet. If

inysia [295]

Answer:

2 feet

Step-by-step explanation:

Let

x ----> the uniform amount added to each side

we know that

The algebraic expression that represent this situation is

$(5+x)(10+x)=84$

solve for x

Apply distributive property

$50+ 5x+10x+x^2=84\\x^2+15x-34=0$

solve the quadratic c equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^2+15x-34=0$

$a=1\\b=15\\c=-34$

substitute in the formula

$x=\frac{-15\pm\sqrt{15^{2}-4(1)(-34)}} {2(1)}$

$x=\frac{-15\pm\sqrt{361}} {2}$

$x=\frac{-15\pm19} {2}$

$x=\frac{-15\pm19} {2}=2$

$x=\frac{-15\pm19} {2}=-17$

therefore

The solution is x=2 ft

8 0

3 years ago

Consider two boxes, one containing one black and one white marble, the other, two black and one white marble. A box is selected

valina [46]

Answer:

$\frac{7}{12}$

Step-by-step explanation:

Probability refers to chance of happening of some event.

Conditional probability is the probability of an event A, given that another event B has already occurred.

$B_1,B_2$ denote the two boxes.

In box $B_1$ :

No. of black balls = 1

No. of white balls = 1

In box $B_2$ :

No. of black balls = 2

No. of white balls = 1

Let B, W denote black and white marble.

So, probability that either of the boxes $B_1,B_2$ is chosen is $\frac{1}{2}$

Probability that a black ball is chosen from box $B_1$ = $\frac{1}{2}$

Probability that a black ball is chosen from box $B_2=\frac{2}{3}$

To find:probability that the marble is black

Solution:

Probability that the marble is black = $\frac{1}{2}(\frac{1}{2} )+\frac{1}{2}(\frac{2}{3})=\frac{1}{4}+\frac{1}{3}=\frac{7}{12}$

6 0

3 years ago

the area of one face of a cube is 36 sq feet. what is the volume of a cube that had edges that are twice as long?

noname [10]

The cube with 1 face with area 36 ft^2 has an edge of 6 ft.

The other cube has edges 2 * 6 = 12 ft long and its volume is 12^3

= 1728 ft^3 (answer).

6 0

3 years ago