Answer:
its 80 on edg
Step-by-step explanation:
Answer:
P(B|A)=0.25 , P(A|B) =0.5
Step-by-step explanation:
The question provides the following data:
P(A)= 0.8
P(B)= 0.4
P(A∩B) = 0.2
Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.
To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:
P(B|A) = P(A∩B)/P(A)
= (0.2) / (0.8)
P(B|A)=0.25
To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:
P(A|B) = P(A∩B)/P(B)
= (0.2)/(0.4)
P(A|B) =0.5
4x^2 - 2xy^2
5xy^2 +
3x^2y
_____________
12x^5y^4-2xy^2
This is so because 4+5+3 is 12, then using laws of indices to add your x and y you get x^5 and y^4
To simplify your answer to the lowest you have it in the form of
3x^2y^2(4x^2y - 2xy^2)
If you multiply this as well you get the same answer I got with the addition
Answer:
for #14, x=10
Step-by-step explanation:
in the graph, 6x = 5x +10 so if x was 10 it would be 60 = 60 so x = 10
Answer:
D
Step-by-step explanation:
The function 
has value F(2) when x = 2 is substituted.
