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Snowcat [4.5K]
3 years ago
11

Whats the square root of 121

Mathematics
1 answer:
AnnyKZ [126]3 years ago
6 0
The square root of 121 is 11
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den301095 [7]

Answer:

48degrees

Step-by-step explanation:

From the circle geometry shown, traingle BDC is an isosceles triangle which shows means that their base angels are the same. Hence;

<B = <C

<CBD + <BCD + <D = 180

<BCD + <BCD + <D =180

2<BCD + <BDC = 180

Get <BCD;

<BCD+ <ECB = 90

<BCD + 48 = 90

<BCD = 90 - 48

<BCD = 42degrees

Get <BDC

2<BCD + <BDC = 180

2(42)+ <BDC = 180

84 + <BDC = 180

<BDC = 180 - 84

<BDC = 96

Since angle at the centre is twice that at the circumference, then;

<BAC = 1/2(<BDC )

<BAC = 96/2

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CAN SOMEONE HELP ME WITH THIS PLEASE AND THANK YOU.
Elena L [17]

Answer:

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Step-by-step explanation:

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3 years ago
Find the value of the expression 74.9+5.23-81.4-16
stich3 [128]

Answer:

To find the value of this expression you need to add and subtract from left to right

74.9+5.23-81.4-16 (add the first two, first)

80.13-81.4-16 (74.9+5.23=80.13) (next subtract the next two)

-1.27-16 (80.13-81.4=-1.27) (Last subtract the last two)

-17.27 (-1.27-16=-17.27)

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Hope this helps ;)

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What would be the answer to this question? I cannot figure it out.
hodyreva [135]

Answer:

Step-by-step explanation:

64 s^{12} - 125 y^{30} = 2^{6} s^{12} - 5³ y^{30} = ( 2² s^{4} )³ - ( 5 y^{10} )³ = ( 4 s^{4} )³ - ( 5 y^{10} )³

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3 years ago
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