Just plug in 2 for p. 3*2 - 2 = 6-2 = 4
Answer:
False
Step-by-step explanation:
Each f(x) increases by 8 therefore this equation is a linear function. If you where to graph it would be a straight line
Hope this helped :)
Answer:
Jelly Bean price per pound = $3.25, Trail Mix price per pound = $1.25
Step-by-step explanation:
Let jb = price per pound of jelly beans
Let tm = price per pound of trail mix
equation 1 -> 6*jb + 2*tm = 22
equation 2 -> 3*jb + 5*tm = 16
simplify equation 1
6*jb + 2tm = 22
2*tm = 22 - 6*jb
divide by 2
tm = 11 - 3*jb
plug this into equation 2
3*jb + 5*tm = 16
3*jb + 5*(11-3*jb) = 16
3*jb + 55 - 15*jb = 16
-12*jb + 55 = 16
-12*jb = 16 - 55
-12*jb = -39
jb = -39/-12
jb = 3.25
then, plug the cost per pound of jelly beans back into the simplified equation 1
tm = 11 - 3*jb
tm = 11 - 3*3.25
tm = 1.25
we are given

We will use rational root theorem to find factors
We can see that
Leading coefficient =1
constant term is 6
so, we will find all possible factors of 6

now, we will check each terms
At x=-2:
We can use synthetic division
we get

so, x+2 will be factor
and we can write our expression from synthetic division as


now, we can find factor of remaining terms

we can use quadratic formula


we can compare our equation with quadratic equation
we get

now, we can plug these values




so, we get

so, we can write factor as

so, we get completely factored form as
...............Answer