9x-5, I guess, not sure, but I'm combining like terms. Hope it's right.
Answer:
47 Ducks and 7 piglets.
Step-by-step explanation:
Lets try 27 of each to start
Ducks Piglets Total legs
27 27 54 + 108 = 162. Too many
30 24 60 + 96 = 156 Too many. Increase the ducks by 10:
40 14 80 + 56 = 136.
50 4 100 + 16 = 116 This < 122 so ducks between 40 and 50..
45 9 90 + 36 = 126 Too high so increase ducks:
46 8 92 + 32 = 124 Close.
47 7 94 + 28 = 122.
I guess your are selecting them without replacement, if so:
a) P(picking one defective) = 3/12
P(picking a 2nd defective) = 2/11
P(picking a 3rd defective) = 1/10
P(1 and 2 and 3 defective) = 3/12 x 2/11 x 1/10 = 1/220 = 0.0045
b) None defective: P( Non Defective) = 9/12 (follow Same logic):
9/12 x 8/11 x 7/10 = 21/55 = 0.38
Second method using combination:
a) ³C₃ / ¹²C₃ = 1/220 0.0045
B) ⁹C3 / ¹²C³ = 21/55 = 0.38
Answer:
yes and the common difference is 3
Step-by-step explanation:
Answer:
$6
Step-by-step explanation:
$26.50 * 20% = $5.30
Leave $6 if pennies dont want to be left