Answer:
11
Step-by-step explanation:
When you plug in -2 for x you get -4(-2) +3
8 +3 = 11
F(-2)=11
Hope this helps, have a nice day
I’m not sure if the 15 is the question number but if it is the answer is 32. use PEMDAS
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Answer:
-0.5
Step-by-step explanation:
- slope=rise/run or y/x in other words(y2-y1/x2-x1)
- (y2-y1) is 3-2 so y2-y1=1
- (x2-x1) is 3-5 so x2-x1= -2
- -1/2 or -0.5 would be the slope.