Answer:
300 gallons this was to easy
Answer:
18 and 27
Step-by-step explanation:
Let x = first (smaller) number
Let y = second (larger) number
Sum of two numbers is 45:
⇒ x + y = 45
The greater number is 9 more than the other number:
⇒ y = x + 9
Substitute y = x + 9 into x + y = 45 and solve for x:
⇒ x + (x + 9) = 45
⇒ 2x + 9 = 45
⇒ 2x = 36
⇒ x = 18
Substitute found value for x into y = x + 9 and solve for y:
⇒ y = 18 + 9
⇒ y = 27
Therefore, the two numbers are 18 and 27
Answer:
Exterior Angle = 36 degrees
Step-by-step explanation:
<u><em>Each interior angle of a regular decagon measures 144 degrees.</em></u>
=> <u><em>We'll subtract 144 from 180 to get the measure of the exterior angle.</em></u>
=> Exterior Angle = 180-144
=> Exterior Angle = 36 degrees
You're forgetting to add how many miles did the taxi drove you, without it, this problem doesn't have a solution, you're not including how many miles were drove additionally, as well as how much money you carry in the first place bud sorry
Answer:
![\dfrac{m^3}{16p^2q^2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bm%5E3%7D%7B16p%5E2q%5E2%7D)
Step-by-step explanation:
Given:
![(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}](https://tex.z-dn.net/?f=%282pm%5E%7B-1%7Dq%5E0%29%5E%7B-4%7D%5Ccdot%20%5Cdfrac%7B%202m%5E%7B-1%7D%20p%5E3%7D%7B2pq%5E2%7D)
1.
![m^{-1}=\dfrac{1}{m}](https://tex.z-dn.net/?f=m%5E%7B-1%7D%3D%5Cdfrac%7B1%7D%7Bm%7D)
2.
![q^0=1](https://tex.z-dn.net/?f=q%5E0%3D1)
3.
![2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}](https://tex.z-dn.net/?f=2pm%5E%7B-1%7Dq%5E0%3D2p%5Ccdot%20%5Cdfrac%7B1%7D%7Bm%7D%5Ccdot%201%3D%5Cdfrac%7B2p%7D%7Bm%7D)
4.
![(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}](https://tex.z-dn.net/?f=%282pm%5E%7B-1%7Dq%5E0%29%5E%7B-4%7D%3D%5Cleft%28%5Cdfrac%7B2p%7D%7Bm%7D%5Cright%29%5E%7B-4%7D%3D%5Cleft%28%5Cdfrac%7Bm%7D%7B2p%7D%5Cright%29%5E4%3D%5Cdfrac%7Bm%5E4%7D%7B%282p%29%5E4%7D%3D%5Cdfrac%7Bm%5E4%7D%7B16p%5E4%7D)
5.
![m^{-1}=\dfrac{1}{m}](https://tex.z-dn.net/?f=m%5E%7B-1%7D%3D%5Cdfrac%7B1%7D%7Bm%7D)
6.
![2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}](https://tex.z-dn.net/?f=2m%5E%7B-1%7D%20p%5E3%3D2%5Ccdot%20%5Cdfrac%7B1%7D%7Bm%7D%5Ccdot%20p%5E3%3D%5Cdfrac%7B2p%5E3%7D%7Bm%7D)
7.
![\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%202m%5E%7B-1%7D%20p%5E3%7D%7B2pq%5E2%7D%3D%5Cdfrac%7B%5Cfrac%7B2p%5E3%7D%7Bm%7D%7D%7B2pq%5E2%7D%3D%5Cdfrac%7B2p%5E3%7D%7Bm%7D%5Ccdot%20%5Cdfrac%7B1%7D%7B2pq%5E2%7D%3D%5Cdfrac%7Bp%5E2%7D%7Bmq%5E2%7D)
8.
![(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}](https://tex.z-dn.net/?f=%282pm%5E%7B-1%7Dq%5E0%29%5E%7B-4%7D%5Ccdot%20%5Cdfrac%7B%202m%5E%7B-1%7D%20p%5E3%7D%7B2pq%5E2%7D%3D%5Cdfrac%7Bm%5E4%7D%7B16p%5E4%7D%5Ccdot%20%5Cdfrac%7Bp%5E2%7D%7Bmq%5E2%7D%3D%5Cdfrac%7Bm%5E3%7D%7B16p%5E2q%5E2%7D)