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aleksley [76]
3 years ago
11

Pls help It worth 21points

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
7 0
V=d/t
=> v=120/(1\frac{3}{4})
v=120/\frac{7}{4}
v=120*4/7
v=480/7 mph
The problem must have an error because the answer is 480/7 and not 7/480 mph.

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PLZZZZZZ HLPPPPP MEEEEEEE how could you find the y coordinate of the midpoint of a vertical line segment with endpoints at (0, 0
emmainna [20.7K]

Answer:

A. Add the endpoints

C. Divide -12 by 2

Step-by-step explanation:

To find the midpoint of the vertical line segment with endpoints (0, 0) and (0, -12).

Step 1: Add the endpoints (y-coordinates)

0+-12=-12

Step 2: Divide -12 by 2

-12/2=-6

Therefore, the y-coordinate of the midpoint of a vertical line segment is -6.

Options A and C are correct.

5 0
3 years ago
Can anyone give me a way to solve geometric sequence?
MArishka [77]
Geometric sequence is Exponential.
Geometric Recursive
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7 0
3 years ago
How would I solve this?
zvonat [6]
Use Pythagorean Theorem which states that in a right triangle:

 a^2+b^2=c^2, where a and b are the legs, and c is the hypotenuse.

24^2+10^2=x^2

Take the square root of both sides to solve for x.

x =  \sqrt{676} = 26

The answer  is 26.


4 0
3 years ago
10 hours to 6 hours percent of change
Novay_Z [31]
60%

I pretty sure this is right
4 0
3 years ago
Read 2 more answers
1. When a cannonball is fired, the equation of its pathway can be modeled by h = -1612 + 128t.
sashaice [31]

Answer:

The maximum height of the ball is 256m

Step-by-step explanation:

Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t

At maximum height, the velocity of the ball is zero.

velocity = dh/dt

velocity = -32t + 128

Since v = 0 at maximum height

0 = -32t+128

32t = 128

t = 128/32

t = 4seconds

The maximum height can be gotten by substituting t = 4 into the modelled equation.

h = -16t² + 128t

h = -16(4)²+128(4)

h = -16(16)+512

h = -256+512

h = 256m

4 0
3 years ago
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