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ddd [48]
3 years ago
14

Help please! Appreciate it much.

Mathematics
1 answer:
sergey [27]3 years ago
5 0
The maximum point will be the point which gives the largest f(x,y) value. The "y" is subtracted and being multiplied by 2 so very small y-value, large x is point (5,0).
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Find x. Round your answer to the nearest tenth of a degree.
Klio2033 [76]

130 degrees is the answer



5 0
3 years ago
Read 2 more answers
Which of the following is a solution to the system of<br> equations?<br> 4 + y = -x<br> y = 2x - 10
kiruha [24]

Answer:

x=3, y= -6

Step-by-step explanation:

make 4+y= -x as equation (1) and make y=2x-10 as equation (2, then you must find a third equation either from equation (1)or (2). If you choose to find equation (3) from (2) it will be y=2x-10 , then substitute equation (3) from (1) because you can't choose (2) , then it will be 4+(2x-10)= -x

the answer will be x =2

substitute x from equation (3)

y=2x-10

y=2 (2)-10

y= -6

3 0
3 years ago
3. Order the integers from least to greatest. 6, 11, 16, –8, –5
Brums [2.3K]
Hello!

The numbers from least to greatest is -8, -5, 6, 11, 16

Hope this helps!
8 0
3 years ago
Read 2 more answers
g 1) The rate of growth of a certain type of plant is described by a logistic differential equation. Botanists have estimated th
alexira [117]

Answer:

a) The expression for the height, 'H', of the plant after 't' day is;

H = \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \cdot t}}

b) The height of the plant after 30 days is approximately 19.426 inches

Step-by-step explanation:

The given maximum theoretical height of the plant = 30 in.

The height of the plant at the beginning of the experiment = 5 in.

a) The logistic differential equation can be written as follows;

\dfrac{dH}{dt} = K \cdot H \cdot \left( M - {P} \right)

Using the solution for the logistic differential equation, we get;

H = \dfrac{M}{1 + A\cdot e^{-(M\cdot k) \cdot t}}

Where;

A = The condition of height at the beginning of the experiment

M = The maximum height = 30 in.

Therefore, we get;

5 = \dfrac{30}{1 + A\cdot e^{-(30\cdot k) \cdot 0}}

1 + A = \dfrac{30}{5} = 6

A = 5

When t = 20, H = 12

We get;

12 = \dfrac{30}{1 + 5\cdot e^{-(30\cdot k) \cdot 20}}

1 + 5\cdot e^{-(30\cdot k) \cdot 20} = \dfrac{30}{12} = 2.5

5\cdot e^{-(30\cdot k) \cdot 20} =  2.5 - 1 = 1.5

∴ -(30·k)·20 = ㏑(1.5)

k = ㏑(1.5)/(30 × 20) ≈ 6·7577518 × 10⁻⁴

k ≈ 6·7577518 × 10⁻⁴

Therefore, the expression for the height, 'H', of the plant after 't' day is given as follows

H = \dfrac{30}{1 + 5\cdot e^{-(30\times 6.7577518 \times 10^{-4}) \cdot t}} =  \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \cdot t}}

b) The height of the plant after 30 days is given as follows

H =  \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \cdot t}}

At t = 30, we have;

H =  \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \times 30}} \approx 19.4258866473

The height of the plant after 30 days, H ≈ 19.426 in.

3 0
3 years ago
If you work overtime you will receive a time and a half for every hour over 40 hours I currently get paid 12.00 and hour I need
Alchen [17]
1.5×12=18
300÷18=16.6667
you need to work close to 17 hours to earn that much when rounded to the nearest number.
7 0
3 years ago
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