The maximum value can be determined by taking the derivative of the function.
(dh/dt) [h(t)] = h'(x) = -9.8t + 6
Set h'(x) = 0 to find the critical point
-9.8t + 6 = 0
-9.8t = -6
t = 6/9.8
Plug the time back into the function to find the height.
h(6/9.8) = -4.9(6/9.8)^2 + 6(6/9.8) + .6
= 2.4
And I don't understand your second question.
Answer:
42
Step-by-step explanation:
42-6 = 36
36*2 = 72
72-40 = 32
32/4 = 8
Answer
Find out the what is the surface area of the pyramid .
To proof
Formula
Surface area of a square pyramid
Where a is the base edge and h be the height .
As given
A square pyramid has a base with side lengths each measuring 40 inches. The pyramid is 21 inches tall, with a slant height of 29 inches.
i.e Base edge = 40 inches
Height = 21 inches
Put values in the above formula
solving
= 1600 + 80 × 29
= 3920 inches²
Therefore the surface area of the pyramid is 3,920 inches²
Hence proved
1) The coordinates of X are (1, -3)
2) When you reflect over a line parallel to the y-axis the x-coordinate does not change, so the x-coordinate of X' is 1.
3) The vertical distance between the point X (1, - 3) and the line y = 1 is 1 - (-3) = 1 + 3 = 4.
4) The vertical distance of the point X' has to ve the same, 4, and the point X' will be 4 units over the line y = 1. That leads to y = 1 + 4 = 5.
So the y-coordinate of the point X' is 5.
5) Conclusion the coordinates of the point X' are x = 1, y = 5, i.e.point (1,5)
Well, following the order of PEMDAS, I got choice B. 52
For instance, when you plug in 5 for x, you get F(5)=2(5)^2+2.
Moreover, following PEMDAS, you're supposed to solve what's inside the parenthesis, but since there is no operation going on inside the parenthesis, then you simple move on to the exponent.
In this case, you square the number 5, which gives you F(5)=2(25)+2
After that, you Multiply (letter M in PEMDAS). This results in F(5)=50+2.
Finally, you add them, which results in F=52.
By the way, I noticed a mistake in your work. When multiplying 2 by 5, the answer is 10, not 20.
Anyway, hope this helped! :-)
