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Vaselesa [24]
3 years ago
8

The smallest unit of size in the list below is the

Mathematics
2 answers:
Neko [114]3 years ago
5 0
D.) Nanometer is the smallest among your options.

It is equal to 10^-9

Hope this helps!
miv72 [106K]3 years ago
3 0
THe answer to your question is e
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Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A? yes, be
mr_godi [17]

Answer:

yes, becoz all the elements of set R is in set A

8 0
3 years ago
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The graph of f(x) = xx is reflected across the x-axis and then across the y-axis to create the graph of function g(x).
V125BC [204]

Now let's examine the statements:

A)The functions have the same range:FALSE the range changed from y ≥ 0 to y ≤ 0

B)The functions have the same domains. FALSE the doman changed from x ≥ 0 to x ≤ 0

C)The only value that is in the domains of both functions is 0. TRUE: the intersection of x ≥ 0 with x ≤ 0 is 0.

D)There are no values that are in the ranges of both functions. FALSE: 0 is in the ranges of both functions.

E)The domain of g(x) is all values greater than or equal to 0. FALSE: it was proved that the domain of g(x) is all values less than or equal to 0.

F)The range of g(x) is all values less than or equal to 0. TRUE: it was proved above.

3 0
4 years ago
Read 2 more answers
1.2.4 journal:Algebraic Properties and expressions
pishuonlain [190]

Answer: https://www.coursehero.com/file/36434863/math-124docx/

<u><em>Step-by-step explanation:  In this WEB you will research for your answer you just need to Signed up i think so </em></u>

<u><em>( you need to copie this web on google )</em></u>

<u><em>If you need help ask me</em></u>

6 0
3 years ago
let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)
statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

\sin (\theta)=\frac{3}{5}

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

x^2+3^2=5^2

Solving for x, we have

\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

\tan (y)=\frac{12}{5}

Describes the following triangle

Using the Pythagorean Theorem again, we have

5^2+12^2=h^2

Solving for h, we have

\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}

To calculate the sine and cosine of the sum

\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}

We can use the following identities

\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}

Using those identities in our problem, we're going to have

\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}

4 0
1 year ago
INPUT SU,0 IF OFF OUTPUT M,0 OUTPUT T,0 OUTPUT W,0 OUTPUT TH,0 OUTPUT F,0 ELSE ON OUTPUT M,0 OUTPUT T,0 OUTPUT W,0 OUTPUT TH,0 O
Karo-lina-s [1.5K]
Why’s it in all caps and what’s the question this doesn’t look like a math equation
3 0
3 years ago
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