<em>Solu</em><em>tion</em><em>:</em>
<em>hypotenuse</em><em>=</em><em>p</em>
<em>perpe</em><em>ndicular</em><em>=</em><em>m</em>
<em>base</em><em>=</em><em>n</em>
<em>According</em><em> </em><em>to</em><em> </em><em>Pythagoras</em><em> </em><em>theorem</em><em>,</em>
<em>h^</em><em>2</em><em>=</em><em>p^</em><em>2</em><em>+</em><em>b</em><em>^</em><em>2</em>
<em>So</em><em> </em><em>the</em><em> </em><em>right </em><em>an</em><em>swer</em><em> </em><em>of</em><em> </em><em>you</em><em>r</em><em> </em><em>question</em><em> </em><em>is</em><em> </em><em>m^</em><em>2</em><em>+</em><em>n^</em><em>2</em><em>=</em><em>p^</em><em>2</em>
<em>Right</em><em> </em><em>ans</em><em>wer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>A</em><em>.</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
I think you just divide the 130 ft by the 40 ft = 3.25 ??
Answer:
6 pencils
18 pencils
Step-by-step explanation:
Given that
36 pencils are in 6 packs
Number of packs = 6
Number of pencils = 36
Number of pencils per pack :
Number of pencils / number of packs :
36 / 6 = 6
Hence, 6 pencils per pack
Number of pencils in 3 packs :
Since 6 pencils are in a pack ;
Then, 3 packs = (3 * 6) = 18 pencils
Answer:
See Below.
Step-by-step explanation:
We want to verify the equation:

We can convert sec(α) to 1 / cos(α):

Multiply both layers of the first fraction by cos(α):

Create a common denominator. We can multiply the first fraction by (1 - cos(α)):

Simplify:

From the Pythagorean Identity, we know that cos²(α) + sin²(α) = 1 or equivalently, 1 - cos²(α) = sin²(α). Substitute:

Subtract:

Distribute:

Rewrite:

Split:

Factor the second fraction, and substitute sin²(α) for 1 - cos²(α):

Factor:

Cancel:

Divide the second fraction by cos(α):

Hence proven.
Answer:
Step-by-step explanation:
If you have given an equation, you see the x and y in it. Just taking second equation and think any common factor between x's variable. With common factor, multiply both and you will find the value of y and put it in any equation, you will find the value of X.