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Oksanka [162]
3 years ago
7

The weight of a basketball is normally distributed with a mean if 17 oz. And a standard version deviation of 2 oz. Suppose 50j0

different basketballs are in a warehouse. How many basketballs weigh more than 19 oz?
Mathematics
2 answers:
ddd [48]3 years ago
7 0

3 basketball because subtract

snow_lady [41]3 years ago
4 0

There would be 3 basketballs?

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If someone reads the book (Gryphon) by Charles baxter what???
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Please answer
SVEN [57.7K]

From the calculation done below, it can be seen that the cost of one orange is 85 cents.

<h3>How do we determine the cost of a product?</h3>

The cost of one orange can be determined as follows:

One dime = 10 cents

2 dollars = 200 cents

Total amount given by Sue to the store clerk = One dime + 2 dollars = 10 cents + 200 cents = 210 cents

Cost of two oranges = Total amount given by Sue to the store clerk –

Change = 210 cents – 40 cents = 170 cents

Cost of one orange = Cost of two oranges / 2 = 170 cents / 2 = 85 cents

Learn more about cost here: brainly.com/question/14844899.

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7 0
2 years ago
rent is putting in a sidewalk that is 1/18 yard thick, 9 yards long, and 1 yard wide. how many cubic yards of cement does he nee
madreJ [45]

Answer:

1/18 x 9 x 1 = .5 cubic yards. Why would you ever waste time asking this....

Step-by-step explanation:

8 0
2 years ago
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the number of three-digit numbers with distinct digits that be formed using the digits 1,2,3,5,8 and 9 is . The probability that
jolli1 [7]

Answer:

a)120

b)6.67%

Step-by-step explanation:

Given:

No. of digits given= 6

Digits given= 1,2,3,5,8,9

Number to be formed should be 3-digits, as we have to choose 3 digits from given 6-digits so the no. of combinations will be

6P3= 6!/3!

      = 6*5*4*3*2*1/3*2*1

      =6*5*4

      =120

Now finding the probability that both the first digit and the last digit of the three-digit number are even numbers:

As the first and last digits can only be even

then the form of number can be

a)2n8 or

b)8n2

where n can be 1,3,5 or 9

4*2=8

so there can be 8 three-digit numbers with both the first digit and the last digit even numbers

And probability = 8/120

                          = 0.0667

                          =6.67%

The probability that both the first digit and the last digit of the three-digit number are even numbers is 6.67% !

5 0
3 years ago
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3. Is this an arithmetic or a geometric sequence? 5, 10, 15, 20, 25, ...
VikaD [51]

Answer:

arithmetric

Step-by-step explanation:

the difference is so simple

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3 years ago
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