okay ....... i'm going to ur other question
Answer:
14
Step-by-step explanation:
I think. sorry if i am wrong
9514 1404 393
Answer:
nπ -π/6 . . . for any integer n
Step-by-step explanation:
tan(x) +√3 = -2tan(x) . . . . . given
3tan(x) = -√3 . . . . . . . . . . . add 2tan(x)-√3
tan(x) = -√3/3 . . . . . . . . . . divide by 3
x = arctan(-√3/3) = -π/6 . . . . use the inverse tangent function to find x
This is the value in the range (-π/2, π/2). The tangent function repeats with period π, so the set of values of x that will satisfy this equation is ...
x = n·π -π/6 . . . . for any integer n
If you would like to solve 2x + 5y = - 13 and 3x - 4y = -8, you can do this using the following steps:
<span>2x + 5y = -13 /*4
3x - 4y = -8 /*5
</span>_________________
8x + 20y = -52
15x - 20y = -40
_________________
8x + 15x + 20y - 20y = -52 - 40
23x = -92 /23
x = -92 / 23
x = -4
<span>2x + 5y = -13
</span>2 * (-4) + 5y = -13
-8 + 5y = -13
5y = -13 + 8
5y = -5
y = -1
(x, y) = (-4, -1)
The correct result would be D.) <span>(-4, -1).</span>
