All categories

3 years ago

Thomas invested $1498 at 6% simple interest per annum

Mathematics

1 answer:

Snezhnost [94]3 years ago

8 0

Answer:

$44.94 interest in 6 months
$1767.64 balance in 3 years

Step-by-step explanation:

a) The simple interest is given by the formula ...

I = Prt

where P is the principal invested at rate r for t years. Putting the given values in the formula, we find ...

I = $1498·0.06·(6/12) = $44.94 . . . . interest earned in 6 months

b) The account balance in 3 years will be the initial principal amount plus earned interest.

A = P(1 +rt) = $1498(1 +0.06·3) = $1767.64 . . . . balance after 3 years

You might be interested in

A pound of chocolate costs 8 dollars. Kelsha buys p pounds. Write an equation to represent the total cost c that Keisha pays.

mote1985 [20]

The equation would be 8 times the amount of pounds bought equals the amount paid.

<h2>Answer:</h2>

8p = c

5 0

3 years ago

What is the volume of this cone?

Murrr4er [49]

Answer:

Volume = 183.26 cubic inches

Step-by-step explanation:

Volume of cone = ⅓πr²h

Where,

r = 5 in.

h = 7 in.

Plug in the values into the formula

Volume = ⅓*π*5²*7

Volume = 183.26 cubic inches (nearest hundredth)

4 0

3 years ago

What is the best first step in solving the equation 3 +<img src="https://tex.z-dn.net/?f=3%5Csqrt%5B6%5D%7Bx%7D" id="TexFormula1

Andreas93 [3]

$3+3\sqrt[6]{x}~~ = ~~5\implies \stackrel{\textit{1st step,-3 to both sides}}{3\sqrt[6]{x}~~ = ~~2}\implies \sqrt[6]{x}=\cfrac{2}{3} \\\\\\ (\sqrt[6]{x})^6=\left( \cfrac{2}{3} \right)^6\implies x=\cfrac{2^6}{3^6}\implies x=\cfrac{64}{729}$

6 0

2 years ago

Please help <br> What is the slope of a line that is parallel to the line shown?

Jlenok [28]

Answer:

m=2/3

Step-by-step explanation:

your answer would be A.

8 0

3 years ago

Read 2 more answers

Review the graph of function f(x).

s344n2d4d5 [400]

The two limits when x tends to zero are:

$\lim_{x \to \ 0^-} f(x) = 1\\\\ \lim_{x \to \ 0^+} f(x) = 0$

<h3 /><h3>How to get the limits when x tends to zero?</h3>

Notice that we have a jump at x = 0.

Then we can take two limits, one going from the negative side (where we will go along the blue line)

And other from the positive side (where we go along the orange line).

We will get:

$\lim_{x \to \ 0^-} f(x) = 1\\\\ \lim_{x \to \ 0^+} f(x) = 0$

Notice that the two limits are different, that means that the function is not a continuous function.

If you want to learn more about limits:

brainly.com/question/5313449

#SPJ1

6 0

2 years ago