90. To get to this answer, you would multiply 6 X 10 and 3 X 10. You would then add the products: 60 + 30 = 90.
Answer:
16.364 miles
Step-by-step explanation:
Speed of Claire = 6 miles per hour
Speed of Megan= 5 miles per hour
Distance from camp site to out post = 18 miles
Time for Claire to travel=18/6= 3 hours
Time for Megan to travel = 18/5 = 3.6 hours
The time they meet will be equal
Claire distance= 18 + x
Megan distance = 18-x
Claire time =( 18+x)/6
Megan Tim =( 18-x)/5
(18+x)/6 =(18-x)/5
5(18+x)= 6(18-x)
90 +5x = 108-6x
11x=18
X=18/11
X=1.636 Miles
So the distance from the Outpost to where they meet = 18-1.636
= 16.364 miles
Answer:
We can be 95% confident that consumers spend between $4.04 and $15.96 less at Store A than the consumers spend at Store B.
Step-by-step explanation:
Confidence Intervals give an estimate as range of values for a statistic concerned at a <em>confidence level</em>.
In this case the statistic is the mean difference between Store A and Store B purchase amounts and the confidence level is 95%.
Confidence Interval can be calculated using M±ME where
- M is the sample mean difference between Store A and Store B purchase amounts
- ME is the margin of error from the mean
The price of one ticket is $ 62.2
<h3><u>Solution:</u></h3>
Given that a performer expects to sell 5000 tickets for an upcoming event
They want to make a total of $ 311, 000 in sales from these tickets
<em><u>To find: price of one ticket</u></em>
Let us assume that all tickets have the same price
Let "a" be the price of one ticket
So the total sales price of $ 311, 000 is obtained from product of 5000 tickets and price of one ticket
Thus the price of one ticket is $ 62.2
Answer: B: 35ab^2c AND 7bc^2
Step-by-step explanation:
