Answer:
hey, there!
Step-by-step explanation:
The given is a point (-6,8) through which a line passes. And is perpendicular to the line y = 2x-4
The equation for point (-6,8) is,
(y-8)= m1(x+6)...........(i)
and given equation is y = 2x-4............(ii)
Now, from equation (ii).
slope (m2)= 2 { as equation (ii) is in the form of y= mx+c where m is a slope}.
Now, For perpendicular,
m1×m2= -1
m1×2= -1
Therefore, m1 = -1/2.
Putting, the value of m1 in equation (i).
(y-8) = -1/2×(x+6)
2(y-8)= -1(x+6)
2y - 16 = -x -6
x+2y-10 = 0......... is the required equation.
Hope it helps...
Answer: The midpoint of segment PQ is the number 2.5
note: 2.5 as a fraction is 5/2; as a mixed number 2.5 converts to 2&1/2
============================================================
Explanation:
Apply the midpoint formula to get the midpoint of -8 and 6
We simply add up the values and divide by 2 and we get (-8+6)/2 = -2/2 = -1
So point Q is at -1 on the number line, which is exactly halfway from R to P
Focus on just points P and Q now. Apply the midpoint formula again
Q = -1
P = 6
(Q+P)/2 = (-1+6)/2 = 5/2 = 2.5
So the midpoint of segment PQ is 2.5
The decimal 2.5 can be written as the mixed number 2&1/2, showing that this new point is exactly halfway between 2 and 3.
Answer:A
Step-by-step explanation:
I have no clue what grade are you in
