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dybincka [34]
3 years ago
6

4. What is the range of the graph below

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

R: (Y| E R {-4<=y<=-1})

Step-by-step explanation:

Just look at where the graph is limited to vertically, in this case -1 and -4.

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Need help pls someone
dimaraw [331]

\sqrt[3]{250a^{11}}=\sqrt[3]{125\cdot2a^{2+9}}=\sqrt[3]{125}\cdot\sqrt[3]{2a^2\cdot a^9}=5\sqrt[3]{2a^2}\cdot\sqrt[3]{a^9}\\\\=5\sqrt[3]{2a^2}\cdot\sqrt[3]{a^{3\cdot3}}=5\sqrt[3]{2a^2}\cdot\sqrt[3]{(a^3)^3}=5\sqrt[3]{2^2}\cdot a^3\\\\=\boxed{5a^3\sqrt[3]{2a^2}}

7 0
3 years ago
A box contains 11 red chips and 4 blue chips. We perform the following two-step experiment: (1) First, a chip is selected at ran
Scilla [17]

Answer:

P(B1) = (11/15)

P(B2) = (4/15)

P(A) = (11/15)

P(B1|A) = (5/7)

P(B2|A) = (2/7)

Step-by-step explanation:

There are 11 red chips and 4 blue chips in a box. Two chips are selected one after the other at random and without replacement from the box.

B1 is the event that the chip removed from the box at the first step of the experiment is red.

B2 is the event that the chip removed from the box at the first step of the experiment is blue. A is the event that the chip selected from the box at the second step of the experiment is red.

Note that the probability of an event is the number of elements in that event divided by the Total number of elements in the sample space.

P(E) = n(E) ÷ n(S)

P(B1) = probability that the first chip selected is a red chip = (11/15)

P(B2) = probability that the first chip selected is a blue chip = (4/15)

P(A) = probability that the second chip selected is a red chip

P(A) = P(B1 n A) + P(B2 n A) (Since events B1 and B2 are mutually exclusive)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/21) + (22/105) = (77/105) = (11/15)

P(B1|A) = probability that the first chip selected is a red chip given that the second chip selected is a red chip

The conditional probability, P(X|Y) is given mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

So, P(B1|A) = P(B1 n A) ÷ P(A)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(A) = (11/15)

P(B1|A) = (11/21) ÷ (11/15) = (15/21) = (5/7)

P(B2|A) = probability that the first chip selected is a blue chip given that the second chip selected is a red chip

P(B2|A) = P(B2 n A) ÷ P(A)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/15)

P(B2|A) = (22/105) ÷ (11/15) = (2/7)

Hope this Helps!!!

5 0
3 years ago
9(m-3)+3m=7m+43 help me please
nikdorinn [45]

Answer:

multiply 9 from m and -3

9m - 27 + 3m = 7m + 43

12m - 27 = 7m + 43

12m - 7m = 43+ 27

5m = 70 cut 70 by 5 in 14 times [ 14 x 5= 70 ]

m = 14 answer ❤️❤️ it is 100% correct now!

6 0
3 years ago
Read 2 more answers
PLEASE HELP Complete the table with the number of sit-ups you have to do sunday so that the mean number of sit-ups per day is 10
klemol [59]

The complete table will be:

Monday - 100\\ Tuesday-65\\ Wednesday- 120\\ Thursday-150\\ Friday-90\\ Saturday- 0\\ Sunday-175

<u><em>Explanation</em></u>

Suppose, the number of sit-ups in Sunday is x

Mean is the simple average of some numbers. <u>For finding the mean number</u> of sit-ups per day, we need to <u>divide the 'total number of sit-ups' by the 'total number of days'</u>.

Here the total number of days is 7 and the total number of sit-ups for 7 days = 100+65+120+150+90+0+x= 525+x

Given that, the mean number of sit-ups per day is 100. So, the equation will be...

\frac{525+x}{7}=100\\ \\ 525+x=700\\ \\ x= 700-525=175

So, the number of sit-ups you have to do Sunday is 175.

6 0
3 years ago
Olive Garden is only 10 square yards in the watermelon plants she wants to grow require two and a half square yards each how man
aleksandr82 [10.1K]
4 because 2.5 x 4 = 10 :)
5 0
3 years ago
Read 2 more answers
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