Answer : p(only z)=0.40 and p(only u)=0.08
Explanation :
We have given that ,
p(u)=0.22,
p(z∪u)=0.62,
p(z)=0.54
By using probability rule of union of 2 events, we have,
p(z)+p(u)-p(z∩u)=p(z∪u)
⇒0.54+0.22-p(z∩u)=0.62
⇒0.76-p(z∩u)=0.62
⇒(-)p(z∩u)=0.62-0.76
⇒(-)p(z∩u)= (-)0.14
⇒p(z∩u)=0.14
Now,
p(only z)=p(z)-p(z∩u)
=0.54-0.14
=0.40
and,
p(only u)=p(u)-p(z∩u)
=0.22-0.14
=0.08
∴ Each probability will be
p(only z)=0.40
p(only u)=0.08
Answer:
2c^2 - 2c - 3
Step-by-step explanation:
Next time, please share the answer choices. Thank you.
Group together the 'c' terms in 2 + 7c – 4c2 – 3c + 4:
2 + 4c and -4c^2 + 4 Then we have:
-4c^2 + 4c + 6
We should reduce this by factoring -2 out of all three terms:
2c^2 - 2c - 3 This is the desired quadratic in standard form.
Answer:
100 times
Step-by-step explanation:
u have to divide to know which is bigger by how many times
