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3 years ago

10

1.Identify and EXPLAIN the ERROR

1 answer:

kondor19780726 [428]3 years ago

5 0

1) The error occurred when you moved the decimal place one spot to the left without changing the exponent of 10 to go along with it.

Not changing the exponent will change the entire value of the answer. By changing 10.35 to 1.035, we made our answer 10 times smaller, so in order to compensate for that, we need to make 10^10 ten times bigger by changing it to 10^11.

2) 10.35 x 10^10 gets changed to:

1.035 x 10^11

3) The strategy we used is to apply proper scientific notation to our answer. We should recognize when we drastically change the value of our original answer.

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He price of a dozen eggs was $1.63. The price rose m dollars. Then the price dropped $0.12 per dozen. Express the current price

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3 years ago

Read 2 more answers

A pair of shoes usally sells for $68. If the shoes are 20% off, and sales tax is 7%, what is the total price of the shoes, inclu

Eduardwww [97]

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3 years ago

A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl

Andrew [12]

Answer: $\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$ or $\dfrac{228}{91885}$ .

Step-by-step explanation:

Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.

The total number of cards in a deck 52

Number of faces cards in a deck = 12

Number of cards not face cards = 40

The total number of combinations of drawing 9 cards out of 52 cards = $^{52}C_9$

Now , the combination of 9 cards such that exactly 6 of them are face cards = $^{12}C_{6}\times^{40}C_3$

Now , the probability that the hand contains exactly 6 face cards will be :-

$\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$

$=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}$

Hence, the probability that the hand contains exactly 6 face cards. is $\dfrac{228}{91885}$ .

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3 years ago