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djverab [1.8K]
3 years ago
6

Write a method called printRangeOfNumbers that accepts a minimum, maximum numbers as parameters and prints each number from mini

mum up to that maximum, inclusive, boxed by curly brackets. For example, consider the following method calls:
Computers and Technology
1 answer:
timama [110]3 years ago
5 0

Answer:

The method in python is as follows:

class myClass:

    def printRange(min,max):

         for i in range(min, max+1):

              print("{"+str(i)+"} ", end = '')

           

Explanation:

This line declares the class

class myClass:

This line defines the method

    def printRange(min,max):

This line iterates from min to max

         for i in range(min, max+1):

This line prints the output in its required format

              print("{"+str(i)+"} ", end = '')

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The value of the mathematical constant e can be expressed as an infinite series: e=1+1/1!+1/2!+1/3!+... Write a program that app
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Answer:

// here is code in c++ to find the approx value of "e".

#include <bits/stdc++.h>

using namespace std;

// function to find factorial of a number

double fact(int n){

double f =1.0;

// if n=0 then return 1

if(n==0)

return 1;

for(int a=1;a<=n;++a)

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// driver function

int main()

{

// variable

int n;

double sum=0;

cout<<"enter n:";

// read the value of n

cin>>n;

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  for (int x = 0; x <= n; x++)

  {

     sum += 1.0/fact(x);

  }

  // print the approx value of "e"

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return 0;

}

Explanation:

Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".

Output:

enter n:12

Approx Value of e is: 2.71828

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