Because your gonna elminate the loners and soon your going to substitute them for numbers
You distribute. First 3,000* 7.Then 600 *7. Then 40*7. Then 9 AM. Add it up Hopefully this helps
Tbh I forgot :)
Answer:
The area of the parallelogram is:_______________________________________________________
in² = 1174 ⅛ in² = 1174.125 in² .
_______________________________________________________Explanation:_______________________________________________________Area of a parallelogram:
_______________________________________________________ A = base * height = b * h ;
From the figure (from the actual "question"):
_______________________________________ b = 50.5 in.
h = 23.25 in.
____________________________________________________________Method 1) A = b * h =
= (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as: 1174 <span>⅛ .
</span>
____________________________________________________________Method 2) A = b * h =
= (50 ½ in) * (23 <span>¼ in) =
= (</span>

in) * (

<span> in) ;
</span>
___________________________________________________________Note: "50 ½ " = [(50*2) + 1 ] / 2 =

;
Note: "23 ¼ " = [(23*4) + 1 ] / 4 =

;
____________________________________________________________
→ A = (

in) * (

in) ;
→ A =

in² =

in² ;
→ A = (9393/8) in² =
→
A =
in² = 1174 ⅛ in² = 1174.125 in² .
________________________________________________________
The answer to your question is 130.
We are given the following:
- parabola passes to both (1,0) and (0,1)
<span> - slope at x = 1 is 4 from the equation of the tangent line </span>
<span>First, we figure out the value of c or the y intercept, we use the second point (0, 1) and substitute to the equation of the parabola. W</span><span>hen x = 0, y = 1. So, c should be equal to 1. The</span><span> parabola is y = ax^2 + bx + 1 </span>
<span>Now, we can substitute the point (1,0) into the equation,
</span>0 = a(1)^2 + b(1) + 1
<span>0 = a + b + 1
a + b = -1 </span>
<span>The slope at x = 1 is equal to 4 which is equal to the first derivative of the equation.</span>
<span>We take the derivative of the equation ,
y = ax^2 + bx + 1</span>
<span>y' = 2ax + b
</span>
<span>x = 1, y' = 2
</span>4 = 2a(1) + b
<span>4 = 2a + b </span>
So, we have two equations and two unknowns,<span> </span>
<span>2a + b = 4 </span>
<span>a + b = -1
</span><span>
Solving simultaneously,
a = 5 </span>
<span>b = -6</span>
<span>Therefore, the eqution of the parabola is y = 5x^2 - 6x + 1 .</span>