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brilliants [131]
3 years ago
15

How many points are needed to determine a unique line segment?

Mathematics
1 answer:
RideAnS [48]3 years ago
3 0

Answer:

the answer is two points determine a unique line segment

~batmans wife dun dun dun.....aka ~serenitybella

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Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes o
Volgvan

Answer:

\frac{4}{15} \\

Step-by-step explanation:

number of the students like brussels sprouts but dislike lima beans = number of these students who dislike lima beans - number of students who dislike lima beans and also dislike brussels sprouts

\frac{2}{3}-\frac{3}{5}* \frac{2}{3} = \frac{2}{3}-\frac{6}{15}=\frac{10}{15}-\frac{6}{15}=\frac{4}{15}\\

8 0
3 years ago
A guitar factory has a cost of production C(x) = 100x + 56000 , where is the number of guitars produced . If the company needs t
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

If the company wants to just break even, that means that the cost to produce 150 guitars is equal to the price they charge to make a 0 profit. The cost of 150 guitars is

C(150) = 100(150) + 56000 and

C(150) = 71000. That's how much it costs to produce 150 guitars. If they want to make nothing at all, they have to sell the 150 guitars for

p(x) = 71000/150 so

p(x) = 473.33 or 474

4 0
3 years ago
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Solve for b.<br> 8^b-1=2^4b+4<br> b=_____
777dan777 [17]
I hope this helps you

7 0
3 years ago
Whats the value of x
Vlad [161]

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8 0
3 years ago
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a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no
Helga [31]

The present age of father is 86 years old and present age of son is 48 years old

<em><u>Solution:</u></em>

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

<em><u>Ten years ago he was twice as old as his son</u></em>

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

38 + x - 10 = 2(x - 10)

28 + x = 2x - 20

2x - x = 28 + 20

x = 48

Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

7 0
3 years ago
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