All categories

3 years ago

In 2008, there were 6.7 * 10^9 people living on earth. What is that number in standardnotation?

Mathematics

1 answer:

snow_lady [41]3 years ago

8 0

Answer:

6,700,000,000

Step-by-step explanation:

Standard Notation is the normal way of writing numbers.

Scientific notation of 6.7 * 10^9 would mean we need to move the decimal point "9" units "to the right" and arrive at our normal standard form of the number.

So, we move 1 decimal place and create 67. Then with the next 8 moves (to the right), we add 8 more zeros, so the number actually becomes:

6,700,000,000

This is 6 billion, 700 million.

This is the normal standard way (standard notation) of writing numbers.

You might be interested in

Please help with this. I don’t understand what I’m doing. It’s due tonight

Sunny_sXe [5.5K]

Answer:

.0006

Step-by-step explanation:

I'm not sure if this is correct.. sorry if this is wrong.. :(

3 0

2 years ago

0.8 is 10 times as great as what decimal

Aleks04 [339]

0.08.
0.8/10 is 0.08
the answer is 0.08

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%20%5C%200%7D%20%5Cfrac%7B%5Csqrt%7Bcos2x%7D-%5Csqrt%5B3%5D%7Bcos3x%7D%20%7D%7

salantis [7]

Answer:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{1}{2}$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

L'Hopital's Rule

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

We are given the limit:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)}$

When we directly plug in x = 0, we see that we would have an indeterminate form:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{0}{0}$

This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)}$

Plugging in x = 0 again, we would get:

$\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \frac{0}{0}$

Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:

$\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)}$

Substitute in x = 0 once more:

$\displaystyle \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)} = \frac{1}{2}$

And we have our final answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

6 0

3 years ago

sid and Jill hiked 4 1/8 miles in the morning and 1 1/7 miles in the afternoon.how many times as far did they hike in the mornin

mote1985 [20]

Your answer is ..
First,
we have to turn our mixed fractions into an improper fraction.
=4 1/8 which is 33/8(4 x 8 + 1).

Our next mixed fraction,
we have 1 1/7 which is 8/7(1 x 7 + 1).

Now, we have the get the same denominator in order to subtract.
SO, both 8 and 7 goes in to 56. So we multiply both mixed fractions to get the same denominator.
(Tip: what ever you do to do numerator, you do to the denominator; and the other way around).
33/8 : 33*7=231 and our denominator, 8*7=56
So our improper fraction now,
231/56

Our next fraction 8/7,
7*8= 56 and our numerator 8*8=64.
=64/56

So, now we subtract.
231-64= 167 and our common denominator. 167/56

Now we divide 167 by 56 which is 2 and remainder is 55.
So, you should end up with a mixed fraction, 2 55/56.

7 0

3 years ago

Volume of a cylinders

const2013 [10]

Answer:

The volume of cylinder is V=πr^2h

7 0

1 year ago

In 2008, there were 6.7 * 10^9 people living on earth. What is that number in standardnotation?​

In 2008, there were 6.7 * 10^9 people living on earth. What is that number in standardnotation?