F(x)=-1/2x^2+4vertex:min or max:axis of symmetry:y-intercept:domain:range:
1 answer:
You might be interested in
Answer:
6*8=48 groups with elements of order 7
Step-by-step explanation:
For this case the first step is discompose the number 168 in factors like this:
And for this case we can use the Sylow theorems, given by:
Let G a group of order where p is a prime number, with
and p not divide m then:
1)
2) All sylow p subgroups are conjugate in G
3) Any p subgroup of G is contained in a Sylow p subgroup
4) n(G) =1 mod p
Using these theorems we can see that 7 = 1 (mod7)
By the theorem we can't have on one Sylow 7 subgroup so then we need to have 8 of them.
Every each 2 subgroups intersect in a subgroup with a order that divides 7. And analyzing the intersection we can see that we can have 6 of these subgroups.
So then based on the information we can have 6*8=48 groups with elements of order 7 in G of size 168
Answer:
Null hypothesis
Alternative hypothesis
The p value is 0.000517, which is less than the significance level 0.01, therefore we reject the null hypothesis and conclude that population mean is not equal to 5.00.
Step-by-step explanation:
It is given that a data set lists earthquake depths. The summary statistics are
Level of significance = 0.01
We need to test the claim of a seismologist that these earthquakes are from a population with a mean equal to 5.00.
Null hypothesis
Alternative hypothesis
The formula for z-value is
The p-value for z=3.4719 is 0.000517.
Since the p value is 0.000517, which is less than the significance level 0.01, therefore we reject the null hypothesis and conclude that population mean is not equal to 5.00.