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3 years ago

What is 1955 divide by 85

2 answers:

5 0

When you divide 1955 by 85 you get 23. Hope I helped. You wouldn't mind helping me out by giving me the brainliest answer :P

SpyIntel [72]3 years ago

3 0

It's 23!!!!!! I already said it

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If you graph 2y+8=6x^2-10x what will be the y intercept?

Rufina [12.5K]

Answer:

Y intercept will be -4.

Step-by-step explanation:

Here we are given our function as

$2y+8=6x^2-10x$

We are asked to determine the y intercept.

The y intercept is the y ordinate of the coordinates of the point at which the graph of the function intersects the y axis.

Please note that the point at which graph cuts the y axis have x=0

Hence in order to determine y intercept we need to put x=0 in our function and solve it for y :

$2y+8=6x^2-10x2y+8=6x^2-10x$

Putting x =0

$2y+8=6x^2-10x2y+8=6(0)^2-10(0)$

$2y+8=6x^2-10x2y+8=0-10(0)$

$2y+8=6x^2-10x2y+8=0$

subtracting both sides by 8

$2y+8=6x^2-10x2y=-8$

dividing both sides by 2

=-4

8 0

3 years ago

Which of the following is not a correct name for the line shown?

Talja [164]

Answer:

Step-by-step explanation:

The line can be named with small latin letters or with two large latin letters which represent two points lying on the line.

Consider all options:

A. Points V and X lie on the line, so you can name the line as VX (true option)

B. Points W and X lie on the line, so you can name the line as WX (true option)

C. p represents the line (small letter given on the diagram) - (true option)

D. You cannot name the line using point V and line p, so this option is false

3 0

2 years ago

Read 2 more answers

BCALLE can u help me *3

sveta [45]

Sin∠R = ST/RS ⇒ ST = RS * sin40° = 9 * 0.6428 ≈ 5.8

3 0

2 years ago

What is the equasion of the line that passes through (0,5) and (2,3)

Annette [7]

The equation for a line is mx + b = y where m is the slope and b is the y intercept. To find the slope, we need to use the equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$m = \frac{5 - 3}{0 - 2}$

$m = \frac{2}{-2}$

$m = -1$

Therefore, m is equal to -1. Normally, we would then have to plug in m and one of the points to find b. However, because the point (0,5) is the y-intercept (the y-intercept is the point on the line where x is equal to 0), we can skip this step and go straight to forming the final equation, which is $y=-1x+5$ .

3 0

2 years ago

At one point the average price of regular unleaded gasoline was $3.41 per gallon. Assume that the standard deviation price per

Aleonysh [2.5K]

Answer:

a) $1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

b) $1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

c) We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

Step-by-step explanation:

Previous concepts and Data given

$\mu =3.41$ reprsent the population mean

$\sigma=0.09$ represent the population standard deviation

The Chebyshev's Theorem states that for any dataset

• We have at least 75% of all the data within two deviations from the mean.

• We have at least 88.9% of all the data within three deviations from the mean.

• We have at least 93.8% of all the data within four deviations from the mean.

Or in general words "For any set of data (either population or sample) and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least: $1-\frac{1}{k^2}$

Part a

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

Part b

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

Part c

We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

3 0

3 years ago