Answer:
f(x) = (1/2)(x-2)^2(x+1)(x+2)
Step-by-step explanation:
You can determine this by looking at the zeroes of the graph. For any zero that goes through the x-axis, the power of that zero is odd. For any zero that that "bounces" from the x-axis, the power of that zero is even.
Starting from left to right, we can see that the first zero, -2, goes through the x-axis. That means (x+2) is raised to an odd power. The second zero, -1, also goes through, so (x+1) is raised to an odd power. The last zero, 2, bounces off the x-axis, so (x-2) is raised to an even power. The only functions that satisfy this criteria are function 1 and 2.
However, we are not done yet. We need to figure out which multiplier value (1/2, 1/4) is correct. To do this, we plug in 0 for x, since we know that the y-intercept is 4. When we plug in 0, we see that f(0) = 4 for the first function. Therefore, the first function is the answer.
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Answer:
Just multiply 60 by 80
Step-by-step explanation:
Step-by-step explanation:
11) x^5
12) 5x^2
13) x+21
14) 2x-8
15) 3^3
=3*3*3
=27
16)2^5
=2*2*2*2*2
=32
17) 5^4
=5*5*5*5
=625
18)2 times a number p squared
19)3 times a number m fifth power
20)the addition of half a number and 2
I wanna day, that both are correct because they substituted the same value into both expressions and the results are the same.
Both squares substitute in 6 and both equal -5.
√8+√18−√32
√2^2·2+√3^2·2−√2^4·2
√2^ 2·√2+√3^2·√2−√2^4·√2
√2 is the answer
