Geometry help don’t take points if I get 70%+ I’ll give some away!!

Mathematics

1 answer:

Natalija [7]3 years ago

7 0

The answer is x = 30

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ILL MARK BRAINLIST PLS HELP

Charra [1.4K]

Answer:

Step-by-step explanation:

Your right I think it's c

8 0

3 years ago

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In this exercise, T: R2 → R2 is a function. For each of the following parts, state why T is not linear. (a) T(a1, a2)= (1, a2) (

DENIUS [597]

Answer:

a) T is not homogeneous
b) T is not additive
c) T is not homogeneous
d) T is not additive
e) T is not additive

Step-by-step explanation:

In each case there is an example where one property of linear functions fails.

a) $T(2(1,0))=T((2,0))=(1,0); 2T((1,0))=2(1,0)=(2,0)$ . These vectors are not equal, then T doesn't satisfy the condition of scalar multiplication (homogeneity).

b) $T((1,2)+(2,3))=T(3,5)=(3,9); T((1,2))+T((2,3))=(1,1)+(2,4)=(3,5)$ . Because these vectors are not equal, T doesn't satisfy the property of vector addition (additivity).

c) $T(\frac{1}{2}(\pi,0))=T((\frac{\pi}{2},0))=(\sin(\frac{\pi}{2}),0)=(1,0); \frac{1}{2}T((\pi,0))=\frac{1}{2}(0,0)=(0,0)$ so T is not homogeneous.

d) $T((-1,0)+(1,0))=T(0,0)=(0,0); T((-1,0))+T((1,0))=(1,0)+(1,0)=(2,0)$ then T is not additive.

e) $T((0,0)+(1,0))=T(1,0)=(2,0); T((0,0))+T((1,0))=(1,0)+(2,0)=(3,0)$ then T is not additive.

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3 years ago

Devon has 14 steel balls of equal weight. If he puts 8 of them in one pan of a balance, and the rest along with a weight of 20 g

astra-53 [7]

Let n be a number of balls: n = 14

In one pan you have 8 balls: 8n
In the other pan you have the rest of balls (14 - 8 = 6) along with a <span>weight of 20 grams = 6n + 20
So the pans are balanced:
8n = 6n + 20

Now, just solve the equation:
8n - 6n = 20
2n = 20
n = 20/2
n = 10
So, you know that a ball weights 10 grams.</span>

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3 years ago

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What is the measure of the radius of the cone in the diagram below?

kondor19780726 [428]

Answer:

Option (2)

Step-by-step explanation:

Radius of the circular base of the cone = $\frac{1}{2}(\text{Diameter of the circular base})$