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bazaltina [42]
3 years ago
6

Sqrt31y^3/9x^6?????????? How to solve?

Mathematics
1 answer:
Veronika [31]3 years ago
8 0

Creative use of formatting may make this problem clearer to me, to other helpers and perhaps to you as well. As typed, your

31y^3

Sqrt31y^3/9x^6 seems to indicate Sqrt( ----------- )

x^6


31y³

or √( ---------- )

x^6


√31 cannot be reduced.


√(y³) = y√y.


√(x^6) = x³



Putting this all together, we get the final answer



√31*y*√³

( --------------- )

x³

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Answer:

The joint probability mass function table is provided below.

Step-by-step explanation:

The experiment consist of drawing 3 balls from an urn containing 5 white and 8 red balls.

The random variable <em>Xi</em> is defined as follows:

<em>Xi</em> = 1; if the ith ball is white

<em>Xi</em> = 0; otherwise.

Then <em>X</em>₁ = the 1st ball is white and <em>X</em>₂ = the 2nd ball is white.

The sample space is as follows:

S = {(X₁ = 0, X₂ = 0), (X₁ = 0, X₂ = 1), (X₁ = 1, X₂ = 0), (X₁ = 1, X₂ = 1)}

Compute the probability of each event in the sample space as follows:

P(X_{1} = 0, X_{2}= 0)=\frac{8}{13} \times\frac{7}{12}=\frac{14}{39}

P(X_{1} = 0, X_{2}= 1)=\frac{8}{13} \times\frac{5}{12}=\frac{10}{39}

P(X_{1} = 1, X_{2}= 0)=\frac{5}{13} \times\frac{8}{12}=\frac{10}{39}

P(X_{1} = 1, X_{2}= 1)=\frac{5}{13} \times\frac{4}{12}=\frac{5}{39}

The joint probability mass function table is provided below.

4 0
3 years ago
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Answer:

in the attachement below

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