Hello,
1: dom f=R
2: img f =R
3: 2x²-x-6=2(x²-2x/4+1/46)-6-1/8=2(x-1/4)²-49/8
Vertex=(1/4,-49,8)
4: roots are -3/2 and 2
2(x-1/4)²-49/8=1/8[(4x-1)²-49]=1/8*(4x+6)(4x-8)
5:
From the vertex to ∞
[-1/4 , ∞)
Answer:
-4,-4
Step-by-step explanation:
(x-3)^2 + (x+5)^2=9^2
(x^2-6x+9) + (x^2+10x+25)=81
2x^2+4x+34=81
2x^2+4x-47=0
From here just use quadratic formula
In order to find the value of g(4)+f(-3), we must substitute those values into the functions first.
Substitute -3 into f(x).
f(x)=x²
f(-3)=(-3)²
f(-3)=9
Substitute 4 into g(x).
g(x)=2x-3
g(4)=2(4)-3
Using the rules of PEMDAS, multiply first then subtract.
g(4)=8-3
g(4)=5
Therefore, if f(-3) is 9 and g(4) is 5, we must add the two values together.
5+9=14
<u>The value of g(4)+f(-3) is 14.</u>
Answer:
See attached
Step-by-step explanation:
The answer is in below picture
