To solve this we need to form 2 equations with only 2 variables. x+4y-5z=-7 2x+y+5z=8 3x+5y=1
15x+10y+15z=35 6x+3y+15z=24 9x+7y=11
Now we need to use these to find x and y 9x+15y=3 9x+7y=11 8y=-8 y=-1 Therefore: x=2 From this we can find that: 2(2)-1+5z=8 Therefore z=1 The answer is x=2, y=-1, z=1
If the Length is 11 and the Width is 3 that makes the area 33. Now if you want all possible answers less than 33 then: L: W: A: 11cm 3cm = 33cm 10cm 2cm = 20cm 9cm 1cm = 9cm
Now that's as low as you can get with whole numbers.
